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stich3 [128]
3 years ago
15

Kym switched cell phone plans, She signed up for a new plan that will save her $3.50 pr month compared to her old cell phone pla

n. The cost of the new phone for an entire year is $294. How much did Kym pay per month under her old phone plan?
Mathematics
1 answer:
Marizza181 [45]3 years ago
7 0

Answer:

Ofc here it is ‧₊✦˚.

and here others if you ever need them : + ✶ ✚᯽ ✜ ✲ ❈  ‧₊✦˚.

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I am confused on how to solve this using L'hopital's<br> lim→0 (5^x - 3^x)/x
kupik [55]

Answer:

Same here

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP LOL<br> solve it then graph it
dybincka [34]

Answer:

Step-by-step explanation:

9.)

z + 3 > 2/3

z > -7/3

You want an unshaded dot on the point -7/3 going towards the right.

10.)

1/2 ≤ c - 3/4

5/4 ≤ c

You want a shaded dot on the point 5/4 going towards the left.

3 0
3 years ago
Which equation is the slope-intercept form of the line that passes through (-3,5) and is parallel to the of y=−2\3x+5
irinina [24]

Answer:

y = -2/3x + 3

Step-by-step explanation:

y = -2/3x + b

5 = -2/3(-3) + b

5 = 2 + b

3 = b

8 0
3 years ago
A total of $37185 is invested at an annual interest rate of 2% compounded quarterly. Find the balance after 11 years.
vazorg [7]
A=37,185×(1+0.02÷4)^(4×11)
A=46,309.97
8 0
3 years ago
A researcher is interested in determining the mean energy consumption of a new
Nana76 [90]

Answer:

The most appropriate  value of the critical value is 2.289.

Step-by-step explanation:

We are given that a researcher takes a random sample of 41 bulbs and determines  that the mean consumption is 1.3 watts per hour with a standard deviation of 0.7.

We have to find that when constructing a 97% confidence interval, which would be the most appropriate  value of the critical value.

Firstly, as we know that the test statistics that would be used here is t-test statistics because we don't know about the population standard deviation.

So, for finding the critical value we will look for t table at (41 - 1 = 40) degrees of freedom at the level of significance will be \frac{1 - 0.97}{2} = 0.015 .

Now, as we can see that in the t table the critical values for P = 1.5% are not given, so we will interpolate between P = 2.5% and P = 1%, i.e;

     \frac{0.015 - 0.025}{0.025-0.01}= \frac{\text{Critcal value}-2.021}{2.021-2.423}

So, the critical value at a 1.5% significance level is 2.289.

7 0
3 years ago
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