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3 years ago

Determine the minimum and maximum cycle times in seconds for a desired output of 500 units in a seven-hour day.

Mathematics

1 answer:

liberstina [14]3 years ago

6 0

Complete question:

Please find the attached file for task table

Answer:

The minimum cycle time is 50 s

The maximum cycle time is 50.4 s

Step-by-step explanation:

Given;

production time, t = 7 hours

desired output = demand, D = 500 units

The minimum cycle Time is given by;

Minimum cycle time = maximum task time, from the table the maximum task time is 50 seconds.

Thus, Minimum cycle time = 50 s

The maximum cycle Time is given by;

$CT = \frac{Production \ time}{D} \\\\CT = \frac{7*3600 s}{500 \ units} \\\\CT = 50.4 \ s$

Thus, Maximum cycle time = 50.4 s

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From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean leng

alexandr402 [8]

Complete Question

From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean length of bass caught in a small lake. A normal distribution was assumed. Using the 90% confidence interval obtain:

a. A point estimate of $\mu$ and its 90% margin of error.

b. A 95% confidence interval for $\mu$ .

Answer:

$\= x = 13.4$ . $E = 2.3$

$10.7 < \mu < 16.1$

Step-by-step explanation:

From the question we are told that

The sample size is n = 18

The 90% confidence interval is (11.1, 15.7)

Generally the point estimate of $\mu$ is mathematically evaluated as

$\= x = \frac{11.1 + 15.7 }{2}$

=> $\= x = 13.4$

Generally the margin of error is mathematically evaluated as

$E = \frac{15.7 - 11.1}{2 }$

=> $E = 2.3$

From the question we are told the confidence level is 90% , hence the level of significance is

$\alpha = (100 - 90 ) \%$

=> $\alpha = 0.10$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the equation for the lower limit of the confidence interval is

$\= x - Z_{\frac{\alpha }{2} } * \frac{s}{\sqrt{18} } = 11.1$

=> $13.4 - 0.3877 s = 11.1$

=> $s = 5.932$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E = 1.96 * \frac{5.932}{\sqrt{18} }$

=> $E = 2.7$

Generally 95% confidence interval is mathematically represented as

$\= x -E < \mu < \=x +E$

=> $13.4 - 2.7 < \mu < 13.4 + 2.7$

=> $10.7 < \mu < 16.1$

3 0

3 years ago

Adalyn earns $42 for mowing lawns for 6 hours. If Adalyn charges at the same rate, how many hours will it takes her to earn $63

inessss [21]

2 hours is how long it would take

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3 years ago

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Theresa mix 3 quarts of yellow paint for every two quarts of blue paint to make the color green if she decides to use 7 quarts o

UNO [17]

Answer:

She will need 10.5 quarts

Step-by-step explanation:

ratio of yellow to blue paint = 3:2

7 ÷ 2 = 3.5

3 x 3.5 = 10.5 quarts

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3 years ago

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Phoenix [80]

Answer:

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The second one you divide 4551 by 37 and round your answer up.

Step-by-step explanation:

So it would be 23*37.

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lesantik [10]

Answer:

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Step-by-step explanation:

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3 years ago