Answer:
The degrees of freedom is 11.
The proportion in a t-distribution less than -1.4 is 0.095.
Step-by-step explanation:
The complete question is:
Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4 if the samples have sizes 1 = 12 and n 2 = 12 . Enter the exact answer for the degrees of freedom and round your answer for the area to three decimal places. degrees of freedom = Enter your answer; degrees of freedom proportion = Enter your answer; proportion
Solution:
The information provided is:

Compute the degrees of freedom as follows:


Thus, the degrees of freedom is 11.
Compute the proportion in a t-distribution less than -1.4 as follows:


*Use a <em>t</em>-table.
Thus, the proportion in a t-distribution less than -1.4 is 0.095.
Answer:
hahahahahahaa that's truly
Answer:
The answer is 12
If you look at the set of data 12 is shown the most or there more then once when the others aren't
Answer:
3. 8y= -7x -12
4. -3y= 4x -12
5. 7y= -2x +4
Do you want me to do the rest?
did you got it??
The rest are:
6. -3y =6x +12
7. -10y= 5x+20
8. 4y=2x +12
We see that the points of the graph of the function never attain a y-value of 0. Thus f is never equal to 0 for real numbers, hence we can disqualify all the necessary answers already (only answer not against this is 2). Nevertheless, we can show that this is the right answer. The graph is called a parabola, so it is represents a second order polynomial. These polynomials have either 2 real or 2 complex solutions. Since this does not have real solutions (at the lowest point of that polynomial the y-value is 4) the correct answer is b).