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3 years ago

Which of the following would most undermine speaker credibility?

SAT

2 answers:

azamat3 years ago

8 0

I agree! Nervous gestures and stuttering

worty [1.4K]3 years ago

3 0

I believe it is (B lack of evidence). Hope it helps

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Jump a little higher than you would for single-bounce jumping. Turn your wrists quickly to let the rope pass under your feet twi

VikaD [51]

Answer:

Explanation:

<h2>I don't understand your question</h2>

8 0

3 years ago

What is one thing that you would say to your parents if you only had 5 minutes left till you die

Liono4ka [1.6K]

Answer:

i would say i love you to them and i want a biggest hug and kiss on a cheek

Explanation:

4 0

3 years ago

Read 2 more answers

This world war ii poster was designed to encourage americans to avoid sharing information that could hurt the war effort. Which

Mrac [35]

There are different kinds of poster. The appeal are used in the poster is to "persuasion". The poster aim to influence or convince the soldiers to carry out their duties without any disturbance or noise.

There are different kinds of appeals in persuasion. They are;

Ethos
Pathos
Logos

Pathos is known to be as an appeal to emotions. This is because, it aim too persuade one's audience by appealing to their feelings.

Learn more about Appeal from

brainly.com/question/2497657

8 0

2 years ago

To compare the average amount of time that canadians and americans spend commuting, a researcher collects a sample of canadians

yKpoI14uk [10]

The standard error of the difference of sample means is 0.444

From the complete question, we have the following parameters

<u>Canadians</u>

Sample size = 50
Mean = 4.6
Standard deviation = 2.9

<u>Americans</u>

Sample size = 60
Mean = 5.2
Standard deviation = 1.3

The standard error of a sample is the quotient of the standard deviation and the square root of the sample size.

This is represented as:

$SE = \frac{\sigma}{\sqrt n}$

The standard error of the Canadian sample is:

$SE_1 = \frac{2.9}{\sqrt{50}}$

So, we have:

$SE_1 = 0.41$

The standard error of the American sample is:

$SE_2 = \frac{1.3}{\sqrt{60}}$

So, we have:

$SE_2 = 0.17$

The standard error of the difference of sample means is then calculated as:

$SE= \sqrt{SE_1^2 + SE_2^2}$

This gives

$SE= \sqrt{0.41^2 + 0.17^2}$

$SE= \sqrt{0.197}$

Take square roots

$SE= 0.444$

Hence, the standard error of the difference of sample means is 0.444