If michael family has 210 acres and each cow take 1/3 acre of grazing how many cattle could their farmland support

1 answer:

7 0

To find the answer,we can divide the arches(210) bythe amount a cattle need( 1/3):

210÷1/3
=210×3
=630

Therefore, the farmland could support 630 cattles.

Hope it helps!

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An experienced landscaper thought it would be funny to play a joke on some rookie landscapers. The rookies were given the measur

pashok25 [27]

Answer:

48∛9 ft²

Step-by-step explanation:

The length (L) and width (W) are given by:

$L = 4\sqrt[3]{24}\\ W= 6\sqrt[3]{3}$

Since this is a rectangular region, the area is given by:

$A=L*W=L \\A=4\sqrt[3]{24}* 6\sqrt[3]{3}\\A=24\sqrt[3]{72}\ ft^2$

The answer can be further simplified by factoring as follows:

$A=24\sqrt[3]{72} = \\A=24\sqrt[3]{2*2*2*3*3}= 24\sqrt[3]{2^3*9}\\A=48\sqrt[3]{9}\ ft^2$

The exact area is its simplest form is 48∛9 ft²

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2 years ago

Consider an m-by-n chessboard with m and n both odd. To fix the notation, suppose that the square in the upper left-hand corner

beks73 [17]

There are two cases to consider.

A) The removed square is in an odd-numbered column (and row). In this case, the board is divided by that column and row into parts with an even number of columns, which can always be tiled by dominos, and the column the square is in, which has an even number of remaining squares that can also be tiled by dominos.

B) The removed square is in an even-numbered column (and row). In this case, the top row to the left of that column (including that column) can be tiled by dominos, as can the bottom row to the right of that column (including that column). The remaining untiled sections of the board have even numbers of rows, so can be tiled by dominos.

_____

Perhaps the shorter answer is that in an odd-sized board, the corner squares are the ones that there is one of in excess. Cutting out one that is of that color leaves an even number of squares, and equal numbers of each color. Such a board seems like it <em>ought</em> to be able to be tiled by dominos, but the above shows there is actually an algorithm for doing so.