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kondaur [170]
3 years ago
13

XYZ Music Store sells new CDs,n, for $ 13.50, and used $6.50 .The store eamed $ 456 revenue last month. The store sold 14 more u

sed CDs than new CDs. Which system of equations represents this scenario?
A.6.5n +13.5U=456;u=n-14
B.13.5n+6.5u=456;u=n+14
C.6.5n +13.5u=456;u+n+14
D.13.5n+6.5u=456;u=n -14
Mathematics
1 answer:
marysya [2.9K]3 years ago
4 0

Answer:

c

Step-by-step explanation:

i did it in a test and i used a calculator

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It’s between two and three which might turn out to be a decimal
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Graph f(x)=−0.5x+3. Use the line tool and select two points to graph the line.
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Answer: These are some points of the grahp:

(-2,4)

(0, 3)

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Explanation:


1) f(x) =  -0.5x + 3, is the equation of the form y = mx + b


2) y = mx + b is slope-intercept  equation of a line where the slope is m and the y-intercept is b, so, f(x) = - 0.5x + b has slope m = -0.5 and y-intercept b = 3.


3) To graph f(x) = -0.5x + 3, follow these steps:

  • draw two perpedicular axis: vertical axis, labeled y, and horizontal axis, labeled x.
  • draw marks on each axis, each mark equivalent to one unit.
  • the intersection point of the vertical and horizontal axis is the origin, i.e. point (0,0).
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        x       f(x) = - 0.5x + 3

        -2         4

        0          3

        2          2

        4           1

        6          0


4) You can see the graph in the figure attached, and select any of the points on the line either by using the table or by using the equation f(x) = -0.5x + 3.

8 0
4 years ago
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Answer:

a) z = 1.645

b) Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

Step-by-step explanation:

Population is approximately normal, so we can find the normal confidence interval.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645. This is the critical value, the answer for a).

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645*\frac{0.0325}{\sqrt{12}} = 0.015

The lower end of the interval is the sample mean subtracted by M. So it is 0.437 - 0.015 = 0.422cc/m³.

The upper end of the interval is the sample mean added to M. So it is 0.437 + 0.015 = 0.452 cc/m³.

b)

Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

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