we
know that if we have a polynomial with real coefients and one root is
a+bi, another root is a-bi
so
some
roots are
3,-4,6+5i,
6-5i
for
roots, r1 and r2
teh
factors are
(x-r1)(x-r2)
so
we
can put them in and
(x-3)(x+4)(x-6-5i)(x-6+5i)
(x^2+x-12)(2x^2-12x+61)
x^4-11x^3+37x^2+205x-732
to
keep the same coefients, we multiply whole thing by c
c(x^4-11x^3+37x^2+205x-732)
we
don't know what c is
we
know that
f(1)=250
f(1)=c(x^4-11x^3+37x^2+205x-732)
find
c
f(1)=c(1^4-11(1^3)+37(1^2)+205(1)-732)=250
f(1)=c(-500)=250
-500c=250
divide
both sides by -500
c=-1/2
the
polynomial (factored with real coefients) is
f(x)=-0.5(x-3)(x+4)(2x^2-12x+61)
The answer is
C.
Adding any positive value to
won't really make
into a rational number, so the way you have to do it add the negative self, -
to make it into 0. Any number plus its negative value would result in 0, which is a rational number.
Answer:
btw it olny 8 points but it is c
Step-by-step explanation:
I am not sure but I do know that you need to have coordinates points in order to be able to graph... so there for you have to make an x/y chart in order to know here to graph...
