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slavikrds [6]
4 years ago
13

Use propeerties to find the sum or product

Mathematics
1 answer:
anyanavicka [17]4 years ago
8 0

to find the sum or product to what


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A heap of grain is shaped as a cone ADCF with height 5 m and base radius 2 m, as shown on the diagram. A and C are points on the
hoa [83]

Answer:

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone ≈ 12.57 m²

Step-by-step explanation:

The given parameters are;

The height of the cone = 5 m

The base radius of the cone  = 2 m

The angle which the A\hat OC = 120°

Therefore, we have;

The angle between [A_F] and the base of the cone = The angle between [CF]  and the base of the cone

The angle between [CF]  and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°  

∴ The angle between [A_F] and the base of the cone = The angle between [CF]  and the base of the cone = 68.2°

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57

The area of the base of the cone ≈ 12.57 m².

8 0
3 years ago
What step of the design process is this: “Used the test results to identify any modifications that they needed to make to improv
sergiy2304 [10]

I dont know how to answer this question

4 0
3 years ago
Question 1: find the volume of a cube whose total surface area is 486cm^2
lapo4ka [179]
<h3>The volume of cube is 729 cubic centimeter</h3>

<em><u>Solution:</u></em>

<em><u>The surface area of cube is given as:</u></em>

Surface\ area = 6a^2

Where, "a" is the length of side of cube

Given that, surface area = 486 square centimeter

486 = 6a^2\\\\a^2 = \frac{486}{6}\\\\a^2 = 81\\\\a = 9

<u><em>Find the volume of cube:</em></u>

volume\ of\ cube = a^3\\\\volume\ of\ cube = 9^3\\\\volume\ of\ cube = 9 \times 9 \times 9\\\\volume\ of\ cube = 729

Thus volume of cube is 729 cubic centimeter

8 0
3 years ago
Determine the standard form of the equation for the circle with center (h,k) = (-5 ½) and radius r =1
wariber [46]
Asuuing yo meant (h,k)=(-5,1/2)

equation is (x-h)^2+(y-k)^2=r^2
(h,k) is center and r=radious
given that (h,k)=(-5,1/2) and r=1
h=-5
k=1/2

(x-(-5))^2+(y- \frac{1}{2} )^2=1^2
(x+5)^2+(y- \frac{1}{2} )^2=1
if you wanted us to expand
x²+y^2+10x-y+25.25=1
8 0
3 years ago
(-11r+14+9r^3) + (3-8r^5+14r^3)
murzikaleks [220]
-8r^5+23r^3-11r+17

Wasn’t Sure What It Was Asking So Hopefully That Works For You
3 0
4 years ago
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