Question

GEOMETRY DESPERATE HELP

Answer 1

Answer: Choice C) $x^2 + (y-2)^2 = 4$

==========================================================

Explanation:

The center is at (0,2). So (h,k) = (0,2) leads to h = 0 and k = 2.

The radius is 2 units, meaning r = 2.

Plug h = 0, k = 2, r = 2 into the formula below and simplify

$(x-h)^2 + (y-k)^2 = r^2\\\\(x-0)^2 + (y-2)^2 = 2^2\\\\x^2 + (y-2)^2 = 4$