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pashok25 [27]
3 years ago
8

The graph below could be the graph of which exponential function

Mathematics
2 answers:
Irina-Kira [14]3 years ago
4 0
The correct answer is C. F(x)=2 * (0.7)^x
Anna71 [15]3 years ago
3 0

Answer:

y=2.(0.5)^{x}

Step-by-step explanation:

Although the options of this question have not been given, but still we can find the function from its graph.

Let the function is,

y=a(b)^{x}

This graph is passing through two points (0, 2) and (1, 1).

By substituting these points in the function we can find the values of a and b,

For (0, 2),

2=a(b)^{0}

a = 2

For (1, 1),

1=2.(b)^{1}

b=\frac{1}{2}

Therefore, given graph represents an exponential function,

y=2.(\frac{1}{2})^{x}

Or,  y=2.(0.5)^{x}

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will ran four miles on his first day of training t next day he ran one third that distance how far did he run the second day
andrew11 [14]
<span>(1/3) * 4 = 4/3 = 1 and 1/3 miles</span>
4 0
4 years ago
A composite figure is formed by combining a square and a triangle. Its total area is 57.5 ft2. The area of the triangle is 32.5
ozzi

Answer:

Area of square = Composite Area - Area of Triangle

                         =    32.5  - 7.5  = 25

Area of square = 25 square feet.

Formula for area of square = s²

s²  = 25

s = √25

s = 5

Length of each side of square = 5 feet.

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3 years ago
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3 plane tickets to Orange County cost $328
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3 years ago
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An angle whose measure is -120 is in standard position. In which quadrant does the terminal side of the angle fall
My name is Ann [436]
I believe it falls in the 3rd quadrant
5 0
4 years ago
12 yds
Anton [14]

Answer:

176 square yards

Step-by-step explanation:

<u><em>The picture of the question in the attached figure N 1</em></u>

we know that

The area of the walkway around the rectangular pool, is equal to the area of two trapezoids (#1 and #2), plus the area of two smaller rectangles (#3 and #4)

see the attached figure N 2 to better understand the problem

step 1

Find the area of the two trapezoids (#1 and #2)

A=2[\frac{1}{2}(b_1+b_2)h]

simplify

A=(b_1+b_2)h

we have

b_1=12\ yd\\b_2=4+12+4=20\ yd\\h=4\ yd

substitute

A=(12+20)(4)=128\ yd^2

step 2

Find the area of the two smaller rectangles (#3 and #4)

A=2[LW]

we have

L=4\ yd\\W=6\ yd

substitute

A=2[(4)(6)]=48\ yd^2

step 3

Find the area of the walkway around the rectangular pool

128+48=176\ yd^2

8 0
4 years ago
Read 2 more answers
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