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pashok25 [27]
3 years ago
8

The graph below could be the graph of which exponential function

Mathematics
2 answers:
Irina-Kira [14]3 years ago
4 0
The correct answer is C. F(x)=2 * (0.7)^x
Anna71 [15]3 years ago
3 0

Answer:

y=2.(0.5)^{x}

Step-by-step explanation:

Although the options of this question have not been given, but still we can find the function from its graph.

Let the function is,

y=a(b)^{x}

This graph is passing through two points (0, 2) and (1, 1).

By substituting these points in the function we can find the values of a and b,

For (0, 2),

2=a(b)^{0}

a = 2

For (1, 1),

1=2.(b)^{1}

b=\frac{1}{2}

Therefore, given graph represents an exponential function,

y=2.(\frac{1}{2})^{x}

Or,  y=2.(0.5)^{x}

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Today, a population of bees contains 58 bees. The population grows exponentially. After 3 weeks, there will be 196 bees. How man
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I believe it’s 653 pls brainliest me
5 0
3 years ago
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Are triangles DEF and LNM similar if DF = 8 and LM = 4?
Alex73 [517]

Answer:

not enough information

Step-by-step explanation:

We know <E is congruent to <N.

We know the lengths of one pair of sides.

That is not enough information to prove that the triangles are similar.

6 0
3 years ago
You pick one card from each set and find the sum. How many different sums are possible?
Bezzdna [24]

Answer:

24 possibilities

Step-by-step explanation:

2*2*6=24

24 possibilities

4 0
3 years ago
Read 2 more answers
Determine the amount needed such that when it comes time for retirement, an individual can make monthly withdraws in the amount
bazaltina [42]

Answer:

The amount needed such that when it comes time for retirement is $396721.78.

Step-by-step explanation:

Given : An individual can make monthly withdraws in the amount of $2,154 for 30 years from an account paying 5.1% compounded monthly.

To find : The amount needed such that when it comes time for retirement?

Solution :

Using the formula of monthly payment,

Monthly payment, M=\frac{\text{Amount}}{\text{Discount factor}}

Discount factor D=\frac{1-(1+i)^{-n}}{i}  

Where,

Amount = ?

Monthly payment  M=$2154

Rate r= 5.1%=0.051

i=\frac{0.05}{12}=0.00425

Time = 30 years  

n=30\times12=360

Substitute all the values,

D=\frac{1-(1+i)^{-n}}{i}

D=\frac{1-(1+0.00425)^{-360}}{0.00425}

D=\frac{1-(1.00425)^{-360}}{0.00425}

D=\frac{1-0.21723}{0.00425}  

D=\frac{0.78277}{0.00425}

D=\$184.1811

Monthly payment, M=\frac{\text{Amount}}{\text{Discount factor}}

2154=\frac{A}{184.1811}

A=2154\times 184.1811  

A=\$396721.778

Nearest cent, A=\$396721.78

Therefore, the amount needed such that when it comes time for retirement is $396721.78.

6 0
4 years ago
How much would you have in your account if you invested $1000 at an interest rate of 8% compounded quarterly for 20 years.​
goblinko [34]

Answer:

A = $4,926.80

Step-by-step explanation:

First, convert R as a percent to r as a decimal

r = R/100

r = 8/100

r = 0.08 rate per year,

Then solve the equation for A

A = P(1 + r/n)nt

A = 1,000.00(1 + 0.08/12)(12)(20)

A = 1,000.00(1 + 0.006666667)(240)

A = $4,926.80

5 0
3 years ago
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