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Hatshy [7]
3 years ago
14

A study conducted at a certain high school shows that 72% of its graduates enroll at a college. Find the probability that among

4 randomly selected graduates, at least one of them enrolls in college.
Mathematics
1 answer:
mixas84 [53]3 years ago
5 0

Answer:

P(X \geq 1) =1-P(X

And we can use the probability mass function and we got:

P(X=0)=(4C0)(0.72)^0 (1-0.72)^{4-0}=0.00615

And replacing we got:

P(X \geq 1) = 1-0.00615 = 0.99385

Step-by-step explanation:

Let X the random variable of interest "number of graduates who enroll in college", on this case we now that:  

X \sim Binom(n=4, p=0.72)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

We want to find the following probability:

P(X \geq 1)

And we can use the complement rule and we got:

P(X \geq 1) =1-P(X

And we can use the probability mass function and we got:

P(X=0)=(4C0)(0.72)^0 (1-0.72)^{4-0}=0.00615

And replacing we got:

P(X \geq 1) = 1-0.00615 = 0.99385

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Out of 300 animals in the zoo 45 are birds what percent are not birds
Leya [2.2K]

Answer:

85%

Step-by-step explanation:

There are two ways to solve this.

1. You can find the percent of birds, and then subtract that from 100%.

To find the percent of birds, divide 45/300 or make the denominator 100 by dividing both parts by 3.

45/300 (as a fraction)

=15/100

That is the same as 15%.

Subtract that from 100% and you get 85%.

2. You find the number of non-bird animals and make that a percent.

300-45=255 non-bird animals

255/300 (as a fraction)

=85/100

That is the same as 85%.

So either way, the answer is 85%.

8 0
3 years ago
14m-13m=17 what is m please help me!!!!
Free_Kalibri [48]

Answer:

<h2>m = 17</h2>

Step-by-step explanation:

14m-13m=17\\\\(14-13)m=17\\\\1m=17\to\boxed{m=17}

3 0
3 years ago
Read 2 more answers
A rain gutter is to be made of aluminum sheets that are 16 inches wide by turning up the edges 90. See the illustration.
goblinko [34]

Based on the width of the aluminum sheets and the angle of the edges, the depth that allows maximum cross-sectional area is 4 inches.

<h3>How much can the maximum cross-sectional area?</h3>

Assuming that the depth is x, the area would be:

= x (16 - 2x)

= 16x - 2x²

The maximum of the parabola is:

x = -b / 2a

= - 16 / (2 x -2)

= -16 / -4

= 4 inches

Find out more on using a parabola to solve for height at brainly.com/question/2274171

#SPJ1

7 0
1 year ago
1 point
egoroff_w [7]

Answer: 35 / 66

Step-by-step explanation:

Given the data bekow:

Outcome : - - - 1 - - - 2 - - - 3 - - - 4 - - - 5 - - - 6

Frequency : - 12 - - - 9 - - - 11 - - 8 - - - 12 - - - 14

What is the experimental probability of spinning an odd

P(spinning an odd) = (number of occurrence of an event / number of trials)

Odd outcomes = 1, 3, 5

Frequency of 1 = 12

Frequency of 3 = 11

Frequency of 5 = 12

Number of occurrences of odd = (12 + 11 + 12) = 35

Number of trials = 66

Therefore,

P(spinning an odd) = 35 / 66

6 0
3 years ago
In a function, every input must go to ______________.
s344n2d4d5 [400]

Answer:

Exactly 1 output

Step-by-step explanation:

4 0
2 years ago
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