Pls help I'm confused, this is due tmr and pls show how you set up the problem, I'll give brainliest!

Mathematics

2 answers:

Anastasy [175]2 years ago

5 0

<h2>Answer:</h2>

Part A:

4% x 33,000 = 1,320

Answer: $1,320 commission

Part B:

I'm a bit confused on what this part is asking but here's my best educated guess.

Answer: The commission will still be 4% of the sales even if the price doubles. No matter how much sales the salesperson earns he will always have a commission of 4%.

enyata [817]2 years ago

3 0

Answer:

$1,320

Step-by-step explanation:

4% of 33,000 commission is 1,320

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Answer:

$e^{4x}=e^4+4e^4(x-1)+8e^4(x-1)^2+...$

$\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n$

Step-by-step explanation:

Taylor series expansions of f(x) at the point x = a

$\text{f}(x)=\text{f}(a)+\text{f}\:'(a)(x-a)+\dfrac{\text{f}\:''(a)}{2!}(x-a)^2+\dfrac{\text{f}\:'''(a)}{3!}(x-a)^3+...+\dfrac{\text{f}\:^{(r)}(a)}{r!}(x-a)^r+...$

This expansion is valid only if $\text{f}\:^{(n)}(a)$ exists and is finite for all $n \in \mathbb{N}$ , and for values of x for which the infinite series converges.

$\textsf{Let }\text{f}(x)=e^{4x} \textsf{ and }a=1$

$\text{f}(x)=\text{f}(1)+\text{f}\:'(1)(x-1)+\dfrac{\text{f}\:''(1)}{2!}(x-1)^2+...$

$\boxed{\begin{minipage}{5.5 cm}\underline{Differentiating $e^{f(x)}$}\\\\If $y=e^{f(x)}$, then $\dfrac{\text{d}y}{\text{d}x}=f\:'(x)e^{f(x)}$\\\end{minipage}}$