Pls help I'm confused, this is due tmr and pls show how you set up the problem, I'll give brainliest!
2 answers:
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Answer:
The probability that his bill will be less than $50 a month or more than $150 for a single month is 0.3728 = 37.28%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
A salesman who uses his car extensively finds that his gasoline bills average $125.32 per month with a standard deviation of $49.51.
This means that
Less than 50:
p-value of Z when X = 50. So
has a p-value of 0.0643
More than 150
1 subtracted by the p-value of Z when X = 150. So
has a p-value of 0.6915
1 - 0.6915 = 0.3085
The probability that his bill will be less than $50 a month or more than $150 for a single month is:
0.0643 + 0.3085 = 0.3728
The probability that his bill will be less than $50 a month or more than $150 for a single month is 0.3728 = 37.28%.