3 years ago

How do I go about solving this system without using matrices? K can be does not exist, is equal to, or does not equal to

Mathematics

1 answer:

Ainat [17]3 years ago

3 0

Answer:

(-∞, 29/7) ∪ (29/7, ∞)

Step-by-step explanation:

The only value of k that will make the system have something other than one solution is the value that puts it in the same proportion as the coefficients in the first equation.

3/21 ≠ k/29

k ≠ 29/7 . . . . . . multiply by 29 and simplify

So, "all values of k" will be ...

(-∞, 29/7) ∪ (29/7, ∞)

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