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3 years ago

Will give brainliest Determine the following values!!!!!

Mathematics

1 answer:

yan [13]3 years ago

5 0

Answer:

x = 26 m∠DAB = 80° m∠ADC = 100°

Step-by-step explanation:

Given,

ABCD is a parallelogram in which AB ║ DC and AD║ BC.

m∠DAB = 4x-24

m∠ADC = 2x+48

Solution,

Since ABCD is a parallelogram so sum of two consecutive angle is 180°.

$m\angle DAB+m\angle ADC=180\°\\4x-24+2x+48=180\°\\6x+24=180\°\\6x=180-24\\6x=156\\x=\frac{156}{6}=26$

Now substituting the value of x we get the value of ∠DAB and ∠ADC .

$m\angle DAB=4x-24=4\times26-24=104-24=80\°$

$m\angle ADC=2x+48=2\times26+48=52+48=100\°$

Thus the value of x is 26 and m∠DAB is 80° and m∠ADC is 100°

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What is three more than the sum of (3,3)

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Step-by-step explanation:

three more than the sum of (3,3)

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three more than means we need to add 3 to 6

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3 years ago

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Find ∠1 and ∠2. Justify your answer.

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Answer:61 degrees

Step-by-step explanation:

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3 years ago

What is the equation for

WARRIOR [948]

The equation of a line that is perpendicular to the given line is y = –4x – 16.

Solution:

The equation of a line given is y = 0.25x – 7

Slope of the given line( $m_1$ ) = 0.25

Let $m_2$ be the slope of the perpendicular line.

Passes through the point (–6, 8).

If two lines are perpendicular then the product of the slopes equal to –1.

$\Rightarrow m_1 \cdot m_2=-1$

$\Rightarrow 0.25\cdot m_2=-1$

$\Rightarrow m_2=\frac{-1}{0.25}$

$\Rightarrow m_2=-4$

Point-slope intercept formula:

$y-y_1=m(x-x_1)$

$x_1=-6, y_1=8$ and $m=-4$

Substitute these in the formula, we get

$y-8=-4(x-(-6))$

$y-8=-4(x+6)$

$y-8=-4x-24$

Add 8 on both sides of the equation.

$y-8+8=-4x-24+8$

$y=-4x-16$

Hence the equation of a line that is perpendicular to the given line is

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3 years ago

In an arithmetic sequence, a_17 = -40 and a_28 = -73. Please explain how to use this information to write a recursive formula fo

Vinvika [58]

An arithmetic sequence

$a_1,a_2,a_3,\ldots,a_n,\ldots$

is one in which consecutive terms of the sequence differ by a fixed number, call it d. This means that, given the first term $a_1$ , we can build the sequence by simply adding d :

$a_2=a_1+d$

$a_3=a_2+d$

$a_4=a_3+d$

and so on, the general pattern governed by the recursive rule,

$a_n=a_{n-1}+d$

We can exploit this rule in order to write any term of the sequence in terms of the first one. For example,

$a_3=a_2+d=(a_1+d)+d=a_1+2d$

$a_4=a_3+d=(a_1+2d)+d=a_1+3d$

and so on up to

$a_n=a_1+(n-1)d$

In this case, we're not given the first term right away, but the 17th. But this isn't a problem; we can use the same exploit to get

$a_{18}=a_{17}+d$

$a_{19}=a_{17}+2d$

$a_{20}=a_{17}+3d$

and so on, up to the next term we know,

$a_{28}=a_{17}+11d=-40+11d$

(Notice how the subscript of a on the right and the coefficient of d add up to the subscript of a on the left.)

The 28th term is -73, so we can solve for d :

$-73=-40+11d\implies -33=11d\implies d=-3$

To get the first term of the sequence, we use the rule found above and either of the known values of the sequence. For instance,

$a_{17}=a_1+16d\implies-40=a_1-16\cdot3\implies a_1=8$

Then the recursive rule for this particular sequence is

$\begin{cases}a_1=8\\a_n=a_{n-1}-3&\text{for }n>1\end{cases}$

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