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mezya [45]
2 years ago
14

⚠️ILL GIVE BRAINIEST, please answer with a full sentence or more. The graph of a quadratic relationship is in the shape of a par

abola. Parabolas are
symmetric arcs and are useful for modeling relationships such as the height of a projectile
over time or the curve of the cables on a suspension bridge. Think about where you have
seen a parabolic arc in real life. What unique features did it have, and where did you see
symmetry in the relationship?
Mathematics
1 answer:
Helga [31]2 years ago
4 0

Answer:

I folded a chainring on my bike so instead of a circle it was more parabolic and it was semi symetric due to the amount of teeth on each side of it.

Step-by-step explanation:

hope it works

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A boat sails 50 km on the bearing of 054º. How far is the ship north of its starting point
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Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 3.0 km/h due east. Runner B is initia
ArbitrLikvidat [17]

Answer:

The distance of the two runners from the flagpole is 0.0882 km

Step-by-step explanation:

We are going to use the minus sign when the runner is on the west and the plus sign when the runner is on the east.

Then, Taking into account  the runner A is 6 km west and is running with a constant velocity of 3 Km/h east, the distance of the runner A from the flagpole is given by the following equation:

Xa = -6 Km + (3 Km/h)* t

Where Xa is the position of the runner A from the flagpole and t is the time in hours.

At the same way the distance of the runner B, Xb, from the flagpole is given by the following equation:

Xb = 7.4 Km - (3.8 Km/h)*t

Then, the two runners cross their path when Xa is equal to Xb, so if we solve this equation for t, we get:

              Xa = Xb

     -6 + (3*t) =  7.4 - (3.8*t)

(3.8*t) + (3*t) = 7.4 + 6

         (6.8*t) = 13.4

                  t = 13.4/6.8

                  t = 1.9706

Therefore, at time t equal to 1.9706 hours, both runners cross their path. The distance of the two runners from the flagpole can be calculated replacing the value of t in equation for Xa or in equation for Xb as:

Xa = -6 Km + (3 Km/h)* t

Xa = -6 Km + (3 Km/h)*(1.9706 h)

Xa = -0.0882 Km

That means that both runners are 0.0882 Km west of a flagpole.

4 0
2 years ago
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