Those lines stand for the absolute value, or how far away it is from zero.
If you draw a number line from -3 to 3, and plot the points x = 2 and x = -2, what similarities do you see?
Although one is two units to the right of 0 and one is two units to the left of 0, both x = 2 and x = -2 are two units away from zero. Therefore, the absolute value of both 2 and -2 is 2.
Answer:
here you goes hope it helps you
Step-by-step explanation:
1
Common factor
−
3
2
+
7
+
2
0
-3y^{2}+7y+20
−3y2+7y+20
−
1
(
3
2
−
7
−
2
0
)
-1(3y^{2}-7y-20)
−1(3y2−7y−20)
2
Use the sum-product pattern
−
1
(
3
2
−
7
−
2
0
)
-1(3y^{2}{\color{#c92786}{-7y}}-20)
−1(3y2−7y−20)
−
1
(
3
2
+
5
−
1
2
−
2
0
)
-1(3y^{2}+{\color{#c92786}{5y}}{\color{#c92786}{-12y}}-20)
−1(3y2+5y−12y−20)
3
Common factor from the two pairs
−
1
(
3
2
+
5
−
1
2
−
2
0
)
-1(3y^{2}+5y-12y-20)
−1(3y2+5y−12y−20)
−
1
(
(
3
+
5
)
−
4
(
3
+
5
)
)
-1(y(3y+5)-4(3y+5))
−1(y(3y+5)−4(3y+5))
4
Rewrite in factored form
Solution
−
1
(
−
4
)
(
3
+
5
)
Answer:
bn+c=
tn=t1+(n-1)d
Step-by-step explanation:
bn+c=
tn=t1+(n-1)d∛²
