1030303030303030 divided by 220202020
2 answers:
<h2>Answer:</h2><h2>103030303030303/22020202</h2><h2>____________________________________</h2><h3>Honey, all you need to do is reduce the expression, if possible, by cancelling the common factors!</h3><h3>Then you'll get your answers:</h3><h3>Exact Form:</h3><h3>103030303030303/22020202</h3><h3>or</h3><h3>
</h3><h3 /><h3>Decimal Form:</h3><h3>4678899.08686137</h3><h3>Mixed Number Form:</h3><h3>4678899 1912705/22020202</h3><h3>or</h3><h3>
</h3><h2>____________________________________</h2><h2>I know this is probably just a troll but your welcome!</h2><h2>Hope you have a good day, Loves~ <3</h2>
You might be interested in
You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.
Answer:
The Confidence interval = (8.98 , 22.18)
Step-by-step explanation:
From the given information:
mean =
mean = 15.58
the standard deviation =
the standard deviation =
standard deviation = 9.62297
Degrees of freedom df = n-1
Degrees of freedom df = 5 - 1
Degrees of freedom df = 4
For df at 4 and 80% confidence level, the critical value t from t table = 1.533
The Margin of Error M.O.E =
The Margin of Error M.O.E =
The Margin of Error M.O.E =
The Margin of Error M.O.E = 6.60
The Confidence interval = ( )
The Confidence interval = ( ,
)
The Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)
The Confidence interval = (8.98 , 22.18)