1030303030303030 divided by 220202020
2 answers:
<h2>Answer:</h2><h2>103030303030303/22020202</h2><h2>____________________________________</h2><h3>Honey, all you need to do is reduce the expression, if possible, by cancelling the common factors!</h3><h3>Then you'll get your answers:</h3><h3>Exact Form:</h3><h3>103030303030303/22020202</h3><h3>or</h3><h3>
</h3><h3 /><h3>Decimal Form:</h3><h3>4678899.08686137</h3><h3>Mixed Number Form:</h3><h3>4678899 1912705/22020202</h3><h3>or</h3><h3>
</h3><h2>____________________________________</h2><h2>I know this is probably just a troll but your welcome!</h2><h2>Hope you have a good day, Loves~ <3</h2>
You might be interested in
Given that the probability <span>is
modeled by the function
![y=3(257,959)^x[tex] where x is the impurity concentration and y, given as a percent, is the probability of the fuse malfunctioning.\\Then, the probability of the fuse malfunctioning for an impurity concentration of 0.17 is given by [tex]y=3(257,959)^{0.17}=3(8.316941)=24.95](https://tex.z-dn.net/?f=y%3D3%28257%2C959%29%5Ex%5Btex%5D%20%20where%20x%20is%20the%20impurity%20%0Aconcentration%20and%20y%2C%20given%20as%20a%20percent%2C%20is%20the%20probability%20of%20the%20fuse%20%0Amalfunctioning.%5C%5CThen%2C%20the%20%3C%2Fspan%3Eprobability%20of%20the%20fuse%20malfunctioning%20for%20an%20impurity%20concentration%20of%200.17%20is%20given%20by%20%5Btex%5Dy%3D3%28257%2C959%29%5E%7B0.17%7D%3D3%288.316941%29%3D24.95)
Therefore, the <span>probability of the fuse malfunctioning for an impurity concentration of 0.17 is 25% to the nearest percent.</span>
</span>
Therefore, the <span>probability of the fuse malfunctioning for an impurity concentration of 0.17 is 25% to the nearest percent.</span>
</span>
Answer:
Step-by-step explanation:
Given
Set: -10 to 10
Required
Write as interval notation
We start by writing the given parameter as an inequality
The direct representation of and
in interval representation of sets is
and
, which shows that the beginning and end of the interval are inclusive;
So, the above inequality in interval notation is: