Hey there! Here's your answer: m<BDC=69 Here's how I got it:<ADC=112; <ADB and <BDC together form <ABD. you would add 6x+7and 12x-3 together to equal 112; 18x+4=112, and solve for x next substitute 6 for x, into m<BDC=12x-3, and simplify! Hope this helps!
