Answer:
4
Step-by-step explanation:
9514 1404 393
Answer:
C {2, 4, 9, 16}
Step-by-step explanation:
The domain is the list of numbers at the tails of the arrows.
The range is the list of numbers at the heads of the arrows: {2, 4, 9, 16}.
Points of inflections are zeroes of the second derivative. We have:
![f(x)=x^3-6x^2+12x\implies f'(x)=3x^2-12x\implies f''(x)=6x-12](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E3-6x%5E2%2B12x%5Cimplies%20f%27%28x%29%3D3x%5E2-12x%5Cimplies%20f%27%27%28x%29%3D6x-12)
So, the second derivative equals zero if and only if
![f''(x)=0\iff 6x-12=0 \iff 6x=12 \iff x=2](https://tex.z-dn.net/?f=f%27%27%28x%29%3D0%5Ciff%206x-12%3D0%20%5Ciff%206x%3D12%20%5Ciff%20x%3D2)
So, this is the only point of inflection of this function.
8.7/2=q/4
multiply both sides by 4: q=8.7/2*4
multiply both sides by 2: 2q=8.7 times 4
refine the equation: 2q=34.8
multiply both sides by 10: 20q=348
Divide both sides by 20: 20q/20=348/20
refine the equation for the final answer: q=87/5
Answer:
<u>Approximately 16 tablets of medicine</u>
Step-by-step explanation:
Based on the information above , we can use a <u>Rule of Three</u> to first figure out how many mg the cat would need to ingest per day.
![\frac{5mg}{1kg} = \frac{x}{4.5kg}](https://tex.z-dn.net/?f=%5Cfrac%7B5mg%7D%7B1kg%7D%20%3D%20%5Cfrac%7Bx%7D%7B4.5kg%7D)
![\frac{5mg*4.5kg}{1kg} = 22.5mg](https://tex.z-dn.net/?f=%5Cfrac%7B5mg%2A4.5kg%7D%7B1kg%7D%20%3D%2022.5mg)
Now we see that the cat needs to take a daily dose of 22.5mg. Since the Tablets come at a strength of 10 mg per tablet then,
![22.5 / 10 = 2.25](https://tex.z-dn.net/?f=22.5%20%2F%2010%20%3D%202.25)
The cat would need to take 2.25 tablets per day. Since she needs to take the dose for the next 7 days then,
![2.25 * 7 = 15.75](https://tex.z-dn.net/?f=2.25%20%2A%207%20%3D%2015.75)
She would need to take<u> approximately 16 tablets of medicine</u> during the week .
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