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A ship is carrying gold bars and silver bars in the ratio 13:17. The ship's load

Using proportions, considering the weight of each bar and the ratio, it is found that the ship is carrying 52 gold bars.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

Each bar weighs 5 kg, and the total weight is of 600 kg, hence the number of bars is given by:

n = 600/5 = 120.

The proportion of gold bars is given by:

p = 13/(13 + 17) = 13/30

Hence, out of 120 bars, the number of gold bars is given by:

nG = 120 x 13/30 = 4 x 13 = 52.

More can be learned about proportions at brainly.com/question/24372153

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4 0

2 years ago

Kevin plans to watch 3 movies each month. Write an equation to represent the total number of movies n that he will watch in m mo

GREYUIT [131]

Answer:

Step-by-step explanation:

n = 3m

6 0

3 years ago

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

<u>e)</u> $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0

3 years ago

Put these numbers in order from least to greatest.<br> 0.65<br> 31.56<br> 6.51<br> 6.5<br> 5.16

liberstina [14]

Answer:

0.65

5.16

6.5

6.51

31.56

Step-by-step explanation:

7 0

3 years ago

Rewrite the function in standard form.<br> f(x)= 3(x + 5)2 - 7

Anna007 [38]

Answer: F= 29
Explanation: first use distributive property and multiplied by three with the parentheses. And then multiply to by what you just solved. Remember to keep writing everything that we haven’t used yet. Then divide both the left side and the 6X by X. Then subtract 30 by 7. And add six. I hope this helped

3 0

3 years ago