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lara [203]
4 years ago
12

A home improvement store advertises 60 square feet of flooring for $287.00 including an $80.00 installation fee. How much does e

ach square feet of flooring cost?
Mathematics
1 answer:
Nutka1998 [239]4 years ago
8 0

Answer:

$4.78 per square foot if the $80.00 is a flat rate, $6.11 if the installation fee is also per square foot.

Step-by-step explanation:

287.00/60 = 4.78

80.00/60 = 1.33

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A triangle ABC has A(1,-4) B(3,-1) C(3,-8).Find the length of the sides AB and AC
mr_godi [17]

Answer:

Step-by-step explanation:

AB=\sqrt{(1^{2} -3^{2})+((-4)^{2} -(-1)^{2} ) }

     =\sqrt{7}

AC=\sqrt{(3^{2} -1^{2} )+((-8)^{2}- (-4)^{2} )} \\

     =\sqrt{56}

4 0
3 years ago
-3² = -1*3² = -1 * 9 = -9 (order of operations) while (-3)² = (-3)(-3) = +9 or 9
mixas84 [53]

Answer:   20

Step-by-step explanation:

Assuming your question is:

Z² - X² - XY     X = -2, Y = 3, Z = -4

Substitute values

(-4)² - (-2)² - {(-2)(3)}

{(-4)(-4)} - {(-2)(-2)} - (-6)

(16) - (4) + 6

16 - 4 + 6

20

6 0
3 years ago
Copy the problems onto your paper, mark the givens and prove the statements asked. Given: ∠BTO ≅ ∠IWE WI ≅ BT , OW ≅ ET Prove: △
Varvara68 [4.7K]

Answer:

\triangle BOT \cong \triangle IEW

Step-by-step explanation:

We are given the following in the question:

\angle BTO \cong \angle IWE\\WI \cong BT\\OT \cong EW

We have to prove:

\triangle BOT \cong \triangle IEW

Proof:

\text{In }\triangle BOT \text{ and } \triangle IEW

we can write:

\angle BTO = \angle IWE\text{ (Given)}\\WI \cong BT\text{ (Given)}\\OT \cong EW\text{ (Given)}

Hence, the two triangle are congruent by SAS congruency rule.

\triangle BOT \cong \triangle IEW

The attached image shows the two triangle.

8 0
3 years ago
HURRY UP PLZZZZZ<br><br>I NEED TO FINISHHHH<br><br>I WILL MARK BRAINLYEST!!!<br>:)
andriy [413]

Answer:

I think 60

Step-by-step explanation:

have a great day

4 0
3 years ago
Read 2 more answers
Define two variables. Write a system of equations, and then solve.
abruzzese [7]

Answer:

Step-by-step explanation:

Assume that the amount needed from the 5% acid is x and that the amount needed from the 6.5% acid is y.

We are given that:

The volume of the final solution is 200 ml

This means that:

x + y = 200

This can be rewritten as:

x = 200 - y .......> equation I

We are also given that:

The concentration of the final solution is 6%

This means that:

5%x + 6.5%y = 6% (x+y)

This can be rewritten as:

0.05 x + 0.065 y = 0.06 (x+y) ............> equation II

Substitute with equation I in equation II and solve for y as follows:

0.05 x + 0.065 y = 0.06 (x+y)

0.05 (200-y) + 0.065 y = 0.06 (200-y+y)

10 - 0.05 y + 0.065 y = 12

0.015y = 12-10 = 2

y = 2/0.015

y = 133.3334 ml

Substitute with the y in equation I to get the x as follows:

x = 200 - y

x = 200 - 133.3334

x = 66.6667 ml

Based on the above calculations:

The amount required from the 5% acid = x = 66.6667 ml

The amount required from the 6.5% acid = y = 133.3334 ml

7 0
3 years ago
Read 2 more answers
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