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Nikitich [7]
2 years ago
13

In ΔABC shown below, ∠BAC is congruent to ∠BCA: Triangle ABC, where angles A and C are congruent Given: Base ∠BAC and ∠ACB are c

ongruent. Prove: ΔABC is an isosceles triangle. When completed (fill in the blanks), the following paragraph proves that Line segment AB is congruent to Line segment BC making ΔABC an isosceles triangle. Construct a perpendicular bisector from point B to Line segment AC. Label the point of intersection between this perpendicular bisector and Line segment AC as point D: m∠BDA and m∠BDC is 90° by the definition of a perpendicular bisector. ∠BDA is congruent to ∠BDC by the definition of congruent angles. Line segment AD is congruent to Line segment DC by _______1________. ΔBAD is congruent to ΔBCD by the _______2________. Line segment AB is congruent to Line segment BC because corresponding parts of congruent triangles are congruent (CPCTC). Consequently, ΔABC is isosceles by definition of an isosceles triangle.
Mathematics
2 answers:
mars1129 [50]2 years ago
7 0

The answer is 1. the definition of congruent angles, 2. the definition of a perpendicular bisector hope this helps!

Morgarella [4.7K]2 years ago
6 0
1. Definition of bisector
2. ASA congruence theorem or ASA Postulate
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Berechne jeweils die Höhe der Pyramiden!<br>a) V = 140 cm3<br>G = 28 cm2<br>h = ?​
kozerog [31]

Answer:

untere Tabelle gibt an, wie Oberfläche und Volumen der Pyramide berechnet werden. Grundsätzlich gilt:

Oberfläche = Grundfläche + Mantelfläche

Volumen = Grundfläche · Pyramidenhöhe : 3

Generell ist darauf zu achten, dass mit unterschiedlichen Höhenangaben gerechnet wird. Für die Berechnung der Oberfläche wird die Höhe der schrägliegenden Seitendreiecke benötigt (Grafik unten: ha; hb). Für die Berechnung des Volumens wird die Höhe der Pyramide benutzt (Grafik unten: h).

JSXGraph v0.95 Copyright (C) see http://jsxgraph.org

ha = 5.83 cm

h = 5.00 cm

a = 6.00 cm

b = 6.01 cm

hb = 5.83 cm

V = 60.10 cm³

Ap = 106.11 cm²

AM = 70.05 cm²

AG = 36.06 cm²

 –  o  +  ←  ↓  ↑  → 

rechteckige Grundflächequadratische GrundflächeOberfläche = Grundfläche + Mantelfläche

OP = AG + AMOP = a · b + a · ha + b · hbOP = a² + a · ha · 2 Volumen = Grundfläche · h : 3

VP = AG · h : 3

VP = a · b · h : 3VP = a² · h : 3

Step-by-step explanation:

#semogamembantu

5 0
3 years ago
A bottle of perfume holds 0.55 onice. A bottle of cologne holds p.2 ounce. How many more ounces dose the bottle of perfume hold?
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It has .33 more ounces if that says .2
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2 years ago
Sidh is making fruit salad. His recipe calls for 3/4 pound of watermelon. He wants
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3/4 x 1/2 = 3/8

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A survey was done to investigate the relationship between liking math and learning a musical
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Answer:

c

Step-by-step explanation:

I took the test dont worry :)

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3 years ago
Read 2 more answers
Can someone help me with this? its solving systems by substitution
yKpoI14uk [10]
Answer: x = 1 and y = 2

Given:
y = -3x + 5
5x - 4y = -3

Since we are given y, let’s sub it in the second equation.

5x - 4(-3x + 5) = -3
5x + 12x - 20 = -3
17x = 17
x = 1

After finding x, we can now find y.

5(1) - 4y = -3
-4y = -8
y = 2

Checking:

y = -3x + 5
2 = -3(1) + 5
2 = 2


5x - 4y = -3
5(1) - 4(2) = -3
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8 0
2 years ago
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