<span>Ray BE bisects </span>∠ABD.
According to picture, this is the solution. In case the question is complete.
The estimated probability would be 0.1... I had this test yesterday. hope this helps
The "standard" parabola with roots 0 and 2 is
All multiples of this parabola, i.e.
have the same roots. We can choose the factor such that the parabola passes through the desided point: if we plug 1, 5 for x, y we have
So, our claim is that the parabola
has roots 0 and 2 and vertex at (1, 5).
You can easily verify this: the roots are guaranteed by the fact that we can write the equation as
The vertex must be at x=1, because it's the midpoint of the roots. Moreover, if we evaluate the function at x=1 we have
as required.
3/2 is more then 1 as a mixed number the totel is 1 1/2
Answer:
y = 6x + 22
General Formulas and Concepts:
<u>Pre-Alg</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
Slope Formula:
Slope-Intercept Form: y = mx + b
Step-by-step explanation:
<u>Step 1: Define</u>
Point (-3, 14)
Point (-1, 16)
<u>Step 2: Find slope </u><em><u>m</u></em>
- Substitute:
- Subtract/Add:
- Divide:
<u>Step 3: Find y-intercept </u><em><u>b</u></em>
- Define: y = 6x + b
- Substitute: 16 = 6(-1) + b
- Multiply: 16 = -6 + b
- Isolate <em>b</em>: 22 = b
- Rewrite: b = 22
<u>Step 4: Write linear equation</u>
y = 6x + 22