I is a good friend and a good uuuuuuyyuyhyyytfikh..
I would say 85:100.....85 out of 100 people
The factors of 32 are 1, 2, 4, 8, 16, and 32.
The factors of 20 are 1, 2, 4, 5, 10, and 20.
The common factors of 32 and 20 are 1, 2, and 4.
The greatest one is 4.
32 = 4 x 8
20 = 4 x 5
32 + 20 = (4 x 8) + (4 x 5)
32 + 20 = <em>4 (8 + 5)</em>
Answer:
m∠A = 20°
Step-by-step explanation:
Given that the sum of the angles of any triangle is 180°, adding the expressions of each angle and setting them equal to 180° will give the value of 'x' and allow you to evaluate the angles.
2x + 5x + 11x = 180
18x = 180
18x/18 = 180/18 or x = 10
m∠A = 2x or 2(10) = 20°
m∠B = 5x or 5(10) = 50°
m∠C = 11x or 11(10) = 110°
Out of the choices given, the only one that is true is that m∠A = 20°.
The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.
That is,
Consider X be the length of the pregnancy
Mean and standard deviation of the length of the pregnancy.
Mean 
Standard deviation \sigma =15
For part (a) , to find the probability of a pregnancy lasting 308 days or longer:
That is, to find 
Using normal distribution,



Thus 
So 




Thus the probability of a pregnancy lasting 308 days or longer is given by 0.00256.
This the answer for part(a): 0.00256
For part(b), to find the length that separates premature babies from those who are not premature.
Given that the length of pregnancy is in the lowest 3%.
The z-value for the lowest of 3% is -1.8808
Then 
This implies 
Thus the babies who are born on or before 238 days are considered to be premature.