1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nuetrik [128]
3 years ago
15

|29. Are the figures similar? Explain.10

Mathematics
2 answers:
Bond [772]3 years ago
6 0
They are not similer because they are facing different ways and they are different sizes
Alexeev081 [22]3 years ago
3 0
Right... they are not the similar, I ca know that because one is obliviously smaller than the other one
You might be interested in
Supplementary angles are two angles whose measures have a sum of 180∘. What is the value of x? Write and solve an equation for x
Evgen [1.6K]
I is a good friend and a good uuuuuuyyuyhyyytfikh..
8 0
3 years ago
About 85% of Americans have Rh positive blood. What is the ratio of Americans that are Rh positive to all Americans?
weqwewe [10]
I would say 85:100.....85 out of 100 people
6 0
3 years ago
Write the sum of 32+20 as the product of their GCF and add another sum
vladimir2022 [97]
The factors of  32  are  1,  2,  4,  8,  16, and  32.

The factors of  20  are  1,  2,  4,  5,  10, and  20.

The common factors of  32  and  20  are  1,  2, and  4.

The greatest one is 4.

32 = 4 x 8

20 = 4 x 5

32 + 20 = (4 x 8) + (4 x 5)

32 + 20  =  <em>4 (8 + 5)</em>
8 0
3 years ago
Triangle abc has the angle mesausres shown. Which statement is true about the angles?
Umnica [9.8K]

Answer:

m∠A = 20°

Step-by-step explanation:

Given that the sum of the angles of any triangle is 180°, adding the expressions of each angle and setting them equal to 180° will give the value of 'x' and allow you to evaluate the angles.  

2x + 5x + 11x = 180

18x = 180

18x/18 = 180/18 or x = 10

m∠A = 2x or 2(10) = 20°

m∠B = 5x or 5(10) = 50°

m∠C = 11x or 11(10) = 110°

Out of the choices given, the only one that is true is that m∠A = 20°.

8 0
3 years ago
The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.
inessss [21]

The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.

That is,

Consider X be the length of the pregnancy

Mean and standard deviation of the length of the pregnancy.

Mean \mu =266\\

Standard deviation \sigma =15

For part (a) , to find the probability of a pregnancy lasting 308 days or longer:

That is, to find P(X\geq 308)

Using normal distribution,

z=\frac{X-\mu}{\sigma}

z=\frac{308-266}{15}

=\frac{42}{15}

Thus z=2.8

So P\left (X\geq 308  \right )=1-P(X

=1-P(z

=1-Table\:  value\:  of\:  2.8

=1-0.99744

=0.00256

Thus the probability of a pregnancy lasting 308 days or longer is given by 0.00256.

This the answer for part(a): 0.00256

For part(b), to find the length that separates premature babies from those who are not premature.

Given that the length of pregnancy is in the lowest 3​%.

The z-value for the lowest of 3% is -1.8808

Then X=\frac{X-\mu}{\sigma}\Rightarrow X=z*\sigma+\mu

This implies X=-1.8808*15+266=237.788

Thus the babies who are born on or before 238 days are considered to be premature.

5 0
3 years ago
Other questions:
  • HELP ME WITH THIS PLEASE!!
    8·2 answers
  • Identify the coordinates help
    13·1 answer
  • A lawyer works for 6.5 hours and charges his client $1,560. What is his hourly rate?
    12·2 answers
  • Wild Water Park
    11·2 answers
  • What is the answer for 5/2 and it is equal to 1/3
    6·1 answer
  • How do you find serface area
    15·2 answers
  • Add: -38+6+27+(-8)+126
    7·1 answer
  • The perimeter of the square below is 36 yards. What is the length of each side?
    5·2 answers
  • What is the name for the perimeter of a circle?
    5·2 answers
  • If x is divided by 2 and then 4 is subtracted, then the function is f left parenthesis x right parenthesis equals x divided by 2
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!