1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vitek1552 [10]
3 years ago
11

At Katya's fruit stand, a basket of strawberries costs $4 and a basket of raspberries costs $9. In one morning, Katya sells 96 b

askets for $644. How many baskets of strawberries were sold
Mathematics
1 answer:
Cloud [144]3 years ago
6 0

44 baskets of strawberries are sold

<em><u>Solution:</u></em>

Let "a" be the number of baskets of strawberries sold

Let "b" be the number of raspberries sold

Cost of 1 basket of strawberries = $ 4

Cost of 1 basket of raspberries = $ 9

<em><u>96 baskets were sold. Therefore, we can say,</u></em>

number of baskets of strawberries + number of raspberries sold = 96

a + b = 96

b = 96 - a ------------- eqn 1

<em><u>In one morning, Katya sells 96 baskets for $644</u></em>

Thus we frame a equation as:

a \times 4 + b \times 9 = 644

4a + 9b = 644 ----------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 1 in eqn 2</u></em>

4a + 9(96 - a) = 644

4a + 864 - 9a = 644

5a = 864 - 644

5a = 220

Divide both sides by 5

a = 44

Thus 44 baskets of strawberries are sold

You might be interested in
Data from Ivy Tech's advising center shows the wait times as a normal distribution with the average as 20 min and a standard dev
fiasKO [112]

9514 1404 393

Answer:

  68%

Step-by-step explanation:

According to the empirical rule, 68% of the distribution lies within 1 standard deviation of the mean.

Here, the mean is 20 and the standard deviation is 5. The bounds on 1 standard deviation from the mean are 20±5 = [15, 25]. This is precisely the interval of interest.

  68% of students wait between 15 and 25 minutes

8 0
2 years ago
Please help me out please
Fantom [35]

Answer:

the area of the hexagon is approx. 187.1 in²

Step-by-step explanation:

Picture this regular polygon as being a hexagon made up of six equilateral triangles of side 12 in.  We find the area of one such triangle and then multiply that by 6 to obtain the total area of the hexagon.

One such equilateral triangle has three sides all of length 12 in, and all the interior angles are 60°.  The height of one such triangle is

h = (12 in)sin 60°, or

                  √3

h = (12 in) -------- = 6√3 in

                     2

So, with base 12 in and height 6√3 in, the area of one such equilateral triangle is

A = (1/2)(12 in)(6√3 in) = 36√3 in²

and the total area of the hexagon is 6(36)√3 in², or approx. 187.1 in²

5 0
3 years ago
Help me it is below
Fofino [41]
I hope this helps you

7 0
3 years ago
Read 2 more answers
HelPPP I need ANSWERS DUEE TOMORROW
aleksley [76]
7. 233
8. 4
9. 6
10. 5
11. 4
12. 7
13. 7
3 0
3 years ago
What point is a solution?
vladimir1956 [14]

(3,2) is the solution

7 0
3 years ago
Read 2 more answers
Other questions:
  • A farmer has 113 sheep. 47 of them are males. How many more female sheep are there than male sheep?
    8·1 answer
  • Point of (0,2) with the slope of -1
    11·1 answer
  • 1,000 grams
    10·1 answer
  • Mrs. Sahd distributes pencils and papers to students in the ratio of 2 pencils to 10 sheets of paper. Three of these ratios are
    15·1 answer
  • Discribe the difference between simple interest and compound interest?
    10·1 answer
  • At the end of a snow storm, Caroline saw there was a lot of snow on her front lawn. The temperature increased and the snow began
    11·1 answer
  • Pls help. I don’t know how to write the explanation
    15·2 answers
  • I need help with this question.
    8·1 answer
  • Classify the triangle by angles and sides and find its area .
    6·1 answer
  • how do i find the type of relationship of a table? whether it is linear or quadradic and how do i find the formula for either re
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!