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3 years ago

Could someone answer the question with the photo linked below? Then explain how to solve it?

Mathematics

1 answer:

san4es73 [151]3 years ago

8 0

Answer:

b = sqrt(57)

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

8^2 + b^2 = 11^2

64+ b^2 = 121

Subtract 64

b^2 = 121-64

b^2 =57

Take the square root of each side

b = sqrt(57)

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2 years ago

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svlad2 [7]

Answer:

300

Step-by-step explanation:

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3 years ago

5.) What is the expanded form of the expression --8(3v – 10)? b.0. 3 c. 0.93 d. 0.9 e. 1.07 a. - 24v + 80

Daniel [21]

The answers are:
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3 years ago

In a bucket, there are 5 red marbles, 3 blue marbles, and 2 green marbles. A marble is chosen randomly and then put back into th

nadezda [96]

Answer:

The required probability is $\frac{1}{10}$ .

Step-by-step explanation:

Probability:

The ratio of the favorable outcomes to the all possible outcomes.

Given that, in a bucket, there are 5 marbles red in color, 3 marbles blue in color and 2 marbles green in color.

Total number of marbles are = 5+3+2= 10

The probability that first marble was red

$=\frac{\textrm{Number of red marbles}}{\textrm{Total number of marbles}}$

$=\frac{5}{10}$

$=\frac12$

The probability that second marble was green is

$=\frac{\textrm{Number of green marbles}}{\textrm{Total number of marbles}}$

$=\frac{2}{10}$

$=\frac15$

The required probability is

$=\frac12 \times \frac15$

$=\frac1{10}$

8 0

3 years ago

Help me pls i keep getting 3/2 but thats not the answer

Gemiola [76]

$\huge\text{Hey there!}$

$\large\boxed{\mathsf{\dfrac{6x^2}{y^3}}}\\\\\large\boxed{= \mathsf{\dfrac{6(4^2)}{4^3}}}\\\\\large\boxed{= \mathsf{\dfrac{6(4\times4)}{4\times4\times4}}}\\\\\large\boxed{= \mathsf{\dfrac{96}{16\times4}}}}\\\\\large\boxed{= \mathsf{\dfrac{96}{64}}}\\\large\boxed{\approx \mathsf{\dfrac{96\div32}{64\div32}}}\\\large\boxed{\approx \mathsf{\dfrac{3}{2} \rightarrow \bf \dfrac{96}{64}}}$

$\huge\text{Thus, your answer is: \boxed{\mathsf{Option\ A. } \ \mathsf{\dfrac{96}{64}}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy}\\\huge\text{your day!}$

~ $\frak{Amphitrite1040:)}$

3 0

2 years ago

Read 2 more answers