Could someone answer the question with the photo linked below? Then explain how to solve it?
1 answer:
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Answer:
3 hours
Step-by-step explanation:
speed of Bharat = 12kilometers / hour
speed of Ingrid=14 kilometers / hour
For this problem we'll be using formula relating time, distance and speed.i.e
Distance = speed x time
Suppose Bharat is riding at a distance of 'b' kilometers, therefore time taken by him will be:
Time = distance/ speed
Time= b/12 hours.
Also, Ingrid can ride the distance at this time with speed of 14km/hr
The distance would be,
Distance = speed x time
Distance = 14 x (b/12) => 14b/12
Distance= 7b/6
Let '' be the distance that Bharat have covered after time 't'
therefore, = 12 x t
Let ' ' be the distance that Ingrid have covered after time 't'
therefore, = 14 x t
In order to find the time when they are 78 kilometers apart, we will add and
, because they are travelling in opposite direction creating distance between them.
So,
+
= 78
( 14 x t) + (12 x t) =78
14t + 12t =78
26t= 78
t= 78/26
t= 3hours.
thus, it will take 3 hours until they are 78 kilometers apart
Base-ten units are used to represent numbers in blocks
<h3>How to represent the bundle of toothpicks</h3>The bundle is given as:
Bundle = 62
Rewrite as:
Bundle = 60 + 2
Express 60 as a product
Bundle = 6 * 10 + 2
See attachment for the drawing that represents the bundle
<h3>Ways to interpret the 6 in 62</h3>
The 6 in 62 can be interpreted in the following ways
- Way 1: 6 tens
- Way 2: 60
Read more about base-ten units at:
Answer: (a). at x = 0, its a removable discontinuity
and at x = 1, it is a jump discontinuity
(b). at x = -3, it is removable discontinuity
also at x = -2, it is an infinite discontinuity
(c). at x = 2, it is a jump discontinuity
Step-by-step explanation:
in this question, we would analyze the 3 options to determine which points gave us discontinuous in the category of discontinuity as jump, removable, infinite, etc.
(a). given that f(x) = x/x² -x
this shows a discontinuous function, because we can see that the denominator equals zero i.e.
x² - x = 0
x(x-1) = 0
where x = 0 or x = 1.
since x = 0 and x = 1, f(x) is a discontinuous function.
let us analyze the function once more we have that
f(x) = x/x²-x = x/x(x-1) = 1/x-1
from 1/x-1 we have that x = 1 which shows a Jump discontinuity
also x = 0, this also shows a removable discontinuity.
(b). we have that f(x) = x+3 / x² +5x + 6
we simplify as
f(x) = x + 3 / (x + 3)(x + 2)
where x = -3, and x = -2 shows it is discontinuous.
from f(x) = x + 3 / (x + 3)(x + 2) = 1/x+2
x = -3 is a removable discontinuity
also x = -2 is an infinite discontinuity
(c). given that f(x) = │x -2│/ x - 2
from basic knowledge in modulus of a function,
│x│= │x x ˃ 0 and at │-x x ∠ 0
therefore, │x - 2│= at │x - 2, x ˃ 0 and at │-(x - 2) x ∠ 2
so the function f(x) = at│ 1, x ˃ 2 and at │-1, x ∠ 2
∴ at x = 2 , the we have a Jump discontinuity.
NB. the figure uploaded below is a diagrammatic sketch of each of the function in the question.
cheers i hope this helps.
