All categories

3 years ago

~15 POINTS~ Please help me with this question.

Mathematics

1 answer:

Step2247 [10]3 years ago

7 0

Divide the actual building's measurements by the replica's measurements.

$\frac{400}{20}=20\\\\\frac{320}{16}=20$

The measurements of the actual building are divided by 20 not 12.
The crew member's calculation is incorrect.

You might be interested in

I need help with this one asap please and thank you

inna [77]

Answer:

Step-by-step explanation:

(m² - 3m + 2) / (m² - m)

we see due to a little bit of experience with expressions and multiplications of expressions that

(m² - 3m + 2) = (m - 2)(m - 1)

(m² - m) = m(m - 1)

so,

(m - 2)(m - 1) / (m(m - 1)) = (m - 2) / m

so, that's not it.

(m² - 2m + 1) / (m - 1)

we see again

(m² - 2m + 1) = (m - 1)(m - 1)

so,

(m - 1)(m - 1) / (m - 1) = m - 1

so, that's not it.

(m² - m - 2) / (m² - 1)

we see again

(m² - m - 2) = (m - 2)(m + 1)

and

(m² - 1) = (m + 1)(m - 1)

so,

(m - 2)(m + 1) / ((m + 1)(m - 1)) = (m - 2) / (m - 1)

yes, that is the solution.

(2m² - 4m) / (2(m - 2))

2m(m - 2) / (2(m - 2)) = 2m/2 = m

no, that is not a solution.

8 0

2 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):