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Alex
3 years ago
7

COMPLETE The equation X-9=0 has how many real solution(s).

Mathematics
1 answer:
Maru [420]3 years ago
5 0

Answer:

one solution

Step-by-step explanation:

X-9=0

Add 9 to each side

X-9+9=0+9

x = 9

There is one solution

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A turtle was swimming 2 feet below the surface of a pond. While looking for food, he went down 7 more feet.
Mekhanik [1.2K]

Answer: 9 feet below or -9 feet

Step-by-step explanation:

   Let us say 0 is the surface of a pond. The turtle started at -2 and then traveled -7 more. We will add these negative values to each other.

-2 + -7 = -2 - 7 = -9

          The turtle is now -9, or 9 feet below, the surface of the pond.

<em>Read more about </em><em>your question</em><em> here:</em>

<em>brainly.com/question/17534933</em>

8 0
2 years ago
Help! What is the area of the triangle in this coordinate plane?
Novay_Z [31]

Answer: B


Step-by-step explanation:

Multiply 4 x 8 which is 32.

Then divide it by 1/2.

The answer is 16.

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3 years ago
Ocean blue sells 179 medium t-shirts. how much money will they receive ? each t shirt costs 10$
aniked [119]

Answer:

the answer is $1790

Step-by-step explanation:

the answer is $1790 because 179 times by 10 will give you 1790 hope this helps :)

3 0
3 years ago
Find the two square roots of each complex number by creating and solving polynomial equations.
son4ous [18]

Answer:

1) w₁=4 - i w₂= -4 + i

2) w₁= 3 - i w₂= -3  + i

3) w₁= 1 + 2i w₂= - 1 - 2i

4) w₁= 2- 3i w₂= -2 + 3i

5) w₁= 5 - 2i w₂= -5 + 2i

6) w₁= 5 - 3i w₂= -5 + 3i

Step-by-step explanation:

The root of a complex number is given by:

\sqrt[n]{z}=\sqrt[n]{r}(Cos(\frac{\theta+2k\pi}{n}) + i Sin(\frac{\theta+2k\pi}{n}))

where:

r: is the module of the complex number

θ: is the angle of the complex number to the positive axis x

n: index of the root

1) z = 15 − 8i  ⇒ r=17 θ= -0.4899 rad

w₁=\sqrt{17}(Cos(\frac{-0.4899}{2}) + i Sin(\frac{-0.4899}{2}))=4-i

w₂=\sqrt{17}(Cos(\frac{-0.4899+2\pi}{2}) + i Sin(\frac{-0.4899+2\pi}{2}))=-1+i

2) z = 8 − 6i  ⇒ r=10 θ= -0.6435 rad

w₁=\sqrt{10}(Cos(\frac{ -0.6435}{2}) + i Sin(\frac{ -0.6435}{2}))= 3 - i

w₂=\sqrt{10}(Cos(\frac{ -0.6435+2\pi}{2}) + i Sin(\frac{ -0.6435+2\pi}{2}))= -3  + i

3) z = −3 + 4i  ⇒ r=5 θ= -0.9316 rad

w₁=\sqrt{5}(Cos(\frac{-0.9316}{2}) + i Sin(\frac{-0.9316}{2}))= 1 + 2i

w₂=\sqrt{5}(Cos(\frac{-0.9316+2\pi}{2}) + i Sin(\frac{-0.9316+2\pi}{2}))= -1 - 2i

4) z = −5 − 12i  ⇒ r=13 θ= 0.4426 rad

w₁=\sqrt{13}(Cos(\frac{0.4426}{2}) + i Sin(\frac{0.4426}{2}))= 2- 3i

w₂=\sqrt{13}(Cos(\frac{0.4426+2\pi}{2}) + i Sin(\frac{0.4426+2\pi}{2}))= -2 + 3i

5) z = 21 − 20i  ⇒ r=29 θ= -0.8098 rad

w₁=\sqrt{29}(Cos(\frac{-0.8098}{2}) + i Sin(\frac{-0.8098}{2}))= 5 - 2i

w₂=\sqrt{29}(Cos(\frac{-0.8098+2\pi}{2}) + i Sin(\frac{-0.8098+2\pi}{2}))= -5 + 2i

6) z = 16 − 30i ⇒ r=34 θ= -1.0808 rad

w₁=\sqrt{34}(Cos(\frac{-1.0808}{2}) + i Sin(\frac{-1.0808}{2}))= 5 - 3i

w₂=\sqrt{34}(Cos(\frac{-1.0808+2\pi}{2}) + i Sin(\frac{-1.0808+2\pi}{2}))= -5 + 3i

6 0
3 years ago
In July, the average temperature in one US city was 29 degrees by December, the average temperature had fallen by 29 degrees. Ex
VikaD [51]

Step-by-step explanation:

In July, it was positive 29 degrees, but in December it was negative 29 degrees. When you have 29-29 you get 0. Hope that helped

4 0
3 years ago
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