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3 years ago

What is the measure of each interior angle of a regular undecagon?

Mathematics

1 answer:

sladkih [1.3K]3 years ago

5 0

Each is 147 degrees thats 1617 Total

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What is the volume of soup that will fit in a cylindrical-shaped can with a height that is 2 inches longer than the radius?

trasher [3.6K]

Answer:

V = πr³ + 2πr²

Step-by-step explanation:

Volume of a cylinder:

V = πr²h

with radius r and height h = 2 + r:

V = πr²(2 + r) = πr³ + 2πr²

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3 years ago

Read 2 more answers

Only need 3.. pls help!!!

Natalka [10]

Answer: I’m not really sure what the correct answer is if you could help that would be great so let me know

Step-by-step explanation:

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3 years ago

How do i find a formula for "1+3+5+7+......+(2n-1)

nata0808 [166]

Answer:

Step-by-step explanation:

common difference d=3-1=2

first term a=1

an=a+(n-1)d

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3 years ago

How do you solve 3 1/2- 2 2/5

Veseljchak [2.6K]

You would first have to find common denominators for the fractions. In this case it would be 10. So your new equation would be 3 5/10 - 2 4/10. Once you do this you can then subtract and solve getting the answer of 1 1/10

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3 years ago

A ladder 16 feet long is leaning against the wall of a tall building. The base of the ladder is moving away from the wall at a r

svet-max [94.6K]

Answer:

a. 0.588

b. 0.0722

c. 4.576 sqft/sec

Step-by-step explanation:

Let b and h denote the base and height as indicated in the diagram. By pythagoras theorem, $h^2 + b^2 = 16^2 = 256 \dotsc\;(1)$ because it is a right angle triangle.

It is given that $\frac{db}{dt} = 1$

Now differentiate (1) with respect to t (time) :

$\displaystyle{2h\frac{dh}{dt} + 2b\frac{db}{dt} = 0 \implies \frac{dh}{dt} = -\frac{b}{h} \frac{db}{dt}}$

$\displaystyle{=-\frac{b}{\sqrt{256 - b^2}} \frac{db}{dt} = -\frac{8}{13.856} \times 1 = -0.588}$

The minus sign indicates that the value of h is actually decreasing. The required answer is 0.588.

b. From the diagram, infer that $16 \sin{\theta} = b$ . When b = 8, then $\theta = \arcsin{0.5} = \ang{30}$ .

Differentiate the above equation w.r.t t

$\displaystyle{16 \cos{\theta} \frac{d\theta}{dt} = \frac{db}{dt} \implies \frac{d\theta}{dt} = \frac{1}{16 \cos{\theta}} = \frac{1}{13.856} = \mathbf{0.0722}}$

c. The area of the triangle is given by $A = 0.5\times h \times b$ . Differentiating w.r.t t,

$\displatstyle{\frac{dA}{dt} = 0.5 b \frac{dh}{dt} + 0.5 h \frac{db}{dt}}$

Plugging in b = 8, h = 13.856, $\frac{dh}{dt} = -0.588$ ,

$\frac{dA}{dt} = -2.352 + 6.928 = \mathbf{4.576 ft^2/sec}$

8 0

4 years ago