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<span>Given the polar coordinate (r,θ), write. x=rcos θ and. y=rsin θ.Evaluate cos θ and. sin θ.Multiply cos θ by. r. to find the x-coordinate of the rectangular form.<span>Multiply sin θ by. r. to find the y-coordinate of the rectangular form.</span></span>
Answer:
Step-by-step explanation:
3x - 4y = 13 (1)
2x + y = 5 (2)
——————
3x - 4y = 13
4(2x + y = 5) (2) times 4
——————-
3x - 4y = 13
8x + 4y = 20
——————-
11x = 33
x = 33/11
x = 3
Plug x = 3 in (2):
2(3) + y = 5
6 + y = 5
y = 5-6
y = -1
Thus, x = 3 and y = -1
(For full answer you might have to go to the comments)
Answer: 28x+30
Explanation: we divide (3x^3-2x^2+4x-3) by (x^2+3x+3) Using long division
3x-11
___________________
(x^2+3x+3) 3x^3-2x^2+4x-3
-(3x^3+9x^2+9x)
__________________
-11x^2-5x-3
-(-11x^2-33x-33)
____________
28x+30
So our remainder will be 28x+30