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Svetradugi [14.3K]
3 years ago
6

Lorena calculated the slope of the linear function that is represented by the table of values as shown. x y –10 15 –8 27 –6 39 –

4 51 –2 63 m = StartFraction y 2 minus y 1 Over x 2 minus x 1 EndFraction = StartFraction 63 minus 51 Over negative 2 minus (negative 4) EndFraction = StartFraction 12 Over negative 6 EndFraction = negative 2. What did she do wrong? She used the wrong formula for slope. She used the wrong points to determine the slope. She made a mistake when she subtracted x 1 from x 2. She made a mistake when she subtracted y 1 from y 2.
Mathematics
2 answers:
Anvisha [2.4K]3 years ago
4 0

She made a mistake when she subtracted x1 from x2.

Step-by-step explanation:

Step 1 :

a)

The formula used by Lorena to calculate the slope between 2 points is correct

So the statement given in option 1 is not the reason for her mistake

Step 2:

b)

She has taken the fourth and fifth point and correctly used the x and y co ordinates to calculate the slope

Hence the statement in second option is not true

Step 3:

c)

While calculating the slope the denominator is -2 - (-4) . This gives 2 as the answer. But she has made a mistake in this subtraction giving -6 as the answer.

Hence she has made a mistake in subtracting x1 from x2 and this statement is true

Step 4:

d)

She has not made any mistake in subtracting y1 from y2. Hence this statement is not true

Nataly [62]3 years ago
4 0

Answer:

she made a mistake when she subtracted y1 from y2

Step-by-step explanation:

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bija089 [108]

Answer:

see explanation

Step-by-step explanation:

73.

18 = 3x\sqrt{3} (divide both sides by 3 )

6 = x\sqrt{3} ( multiply both sides by \sqrt{3} )

6\sqrt{3} = 3x [ \sqrt{3} × \sqrt{3} = 3 ]

divide both sides by 3

x = 2\sqrt{3}

74.

24 = 2x\sqrt{2} ( divide both sides by 2 )

12 = x\sqrt{2} ( multiply both sides by \sqrt{2} )

12\sqrt{2} = 2x ( divide both sides by 2 )

x = 6\sqrt{2}

75.

9\sqrt{2} × x = 18\sqrt{2} ( divide both sides by 9\sqrt{2} )

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76.

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8 0
4 years ago
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Write the equation in slope intercept form with a slope of -3 and passes through (1,4)
vichka [17]
Y = mx + b, where m = slope, and b = y-intercept.

Since you are not given the y-intercept, you have to solve for it through the equation, y = -3x (which is the slope you are given) + b, and replace x and y with values given, which are (1,4)

y = -3x + b
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4 = -3 + b
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Then replace b in the first equation to get the answer
y = -3x + 7
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4 years ago
In a race 24 out of 25 cyclists finished in less than 51 minutes what percentage of cyclists finished the race in less then 51 m
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Answer: 96%

Step-by-step explanation:

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In percentage this would be:

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Answer:

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Step-by-step explanation:

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Suppose you earn 3% on a $1,200 deposit for 5 years. Explain how the simple interest is affected if the rate is increased by 1%.
coldgirl [10]
\bf ~~~~~~ \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$1200\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &5
\end{cases}
\\\\\\
I=1200(0.03)(5)\implies \boxed{I=180}\\\\
-------------------------------

\bf ~~~~~~ \textit{Simple Interest Earned increased by 1\%}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$1200\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
t=years\to &5
\end{cases}
\\\\\\
I=1200(0.04)(5)\implies \boxed{I =240}\\\\
-------------------------------

\bf ~~~~~~ \textit{Simple Interest Earned increased by 1 year}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$1200\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &6
\end{cases}
\\\\\\
I=1200(0.03)(6)\implies \boxed{I =216}
8 0
4 years ago
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