Answer:
x=16/113
Step-by-step explanation:
look at them in order
Answer:
Step-by-step explanation:
step 1
Find the volume of the tank
step 2
we know that
If the tank is 1/3 full of water
then
the volume of water required to completely fill the tank is equal to 2/3 of the tank capacity
so
The worksheet pic is not clear
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
Answer:
9.9
Step-by-step explanation:
\text{Volume of Hemisphere}\text{:}
Volume of Hemisphere:
\,\,257
257
\text{Volume of Sphere}\text{:}
Volume of Sphere:
\,\,514
514
Double volume of hemisphere to get volume of the entire sphere
\text{Volume of a Sphere:}
Volume of a Sphere:
V=\frac{4}{3}\pi r^3
V=
3
4
πr
3
514=
514=
\,\,\left(\frac{4}{3}\pi\right) r^3
(
3
4
π)r
3
514=
514=
\,\,(4.1887902)r^3
(4.1887902)r
3
Evaluate 4/3pi in calc
\frac{514}{4.1887902}=
4.1887902
514
=
\,\,\frac{(4.1887902)r^3}{4.1887902}
4.1887902
(4.1887902)r
3
Evaluate \frac{4}{3}\pi
3
4
π in calc
122.7084611=
122.7084611=
\,\,r^3
r
3
\sqrt[3]{122.7084611}=
3
122.7084611
=
\,\,\sqrt[3]{r^3}
3
r
3
Cube root both sides
4.9692575=
4.9692575=
\,\,r
r
\text{Then the diameter equals }9.938515
Then the diameter equals 9.938515
diameter is radius times 2
\text{Final Answer:}
Final Answer:
d\approx 9.9\text{ m}
d≈9.9 m
Round to nearest tenth
