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vladimir2022 [97]
3 years ago
6

Subject Section 1 Section 2 Section 3 Total

Mathematics
2 answers:
kakasveta [241]3 years ago
6 0

Answer:

9 : 13

Step-by-step explanation:

Given in the question,

for the subject "Basic Mathematics" there are 18 students in section 3 and for subject "Statistics" there are 26 students in section 3.

The ratio of the number of students scheduled for section 3 of Basic Mathematics to the number of students scheduled for section 3 of Statistics

18 : 26

9 : 13

sveta [45]3 years ago
3 0

Answer:

The rario is 9:13.

Step-by-step explanation:

In this case, our population is the number of students in section 3.

Then, in section 3 there are students who were assigned to basic mathematics and there is a group of students who were assigned statistics.

Let's call x students in section 3 assigned to mathematics and let v call the number of students assigned to section 3 statistics.

SW

x = 18\\v = 26\\

We can say then that the relation between the variables x and v is:

\frac{x}{v} = \frac{18}{26} = \frac{9}{13}

this is

x:y = 18:26

Simplifying we have:

9:13.

This means that in section 3 there are 9 students in the basic mathematics course for every 13 students of statistics

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1. The three salespeople for a local advertising firm are Sara, Kenny, and Leila. Sara sold $3350 in ads, Kenny sold $1368, and
Dominik [7]

Answer:

\text{Fraction of Sara sold }= \dfrac{1675}{2587}

\text{Fraction of Kenny sold }= \dfrac{684}{2587}

\text{Fraction of Leila sold }= \dfrac{228}{2587}

Step-by-step explanation:

The three salespeople for a local advertising firm are sara, Kenny and Leila.

Sara sold total ads = $3350

Kenny sold total ads = $1368

Leila sold total ads = $456

First we calculate total sale of all three = 3350 + 1368 + 456 = $5174

We need to find fraction of total sale with each person sell.

\text{Fraction of Sara sold }=\dfrac{\text{Sara total sold}}{\text{Total sale by all three}}

\text{Fraction of Sara sold }=\dfrac{3350}{5174}\Rightarrow\dfrac{1675}{2587}\approx 64.75\%

\text{Fraction of Kenny sold }=\dfrac{\text{Kenny total sold}}{\text{Total sale by all three}}

\text{Fraction of Kenny sold }=\dfrac{1368}{5174}\Rightarrow\dfrac{684}{2587}\approx 26.45\%

\text{Fraction of Leila sold }=\dfrac{\text{Leila total sold}}{\text{Total sale by all three}}

\text{Fraction of Leila sold }=\dfrac{456}{5174}\Rightarrow\dfrac{228}{2587}\approx 8.8\%

4 0
3 years ago
Malcolm took 18 minutes to do 15 math problems. Diedra took 17 minutes to do 16 math problems. Which student did more problems p
boyakko [2]

The student that did more maths problems per minute is Diedra.

In order to determine which student did more maths problems per minute, the rate of each student has to be determined. Rate is the total questions solved divided by the time.

Rate = total questions / total time

Malcolm = 15 / 18 = 0.833 problems per minute

Diedra = 16/ 17 = 0.941 problems per minute

To learn more about rate, please check: brainly.com/question/9834403

3 0
2 years ago
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mixer [17]
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4 years ago
Susie spent $78 in 3 hours. How much did Susie spend per hour?
mart [117]

Answer:

$26

Step-by-step explanation:

78 divided by 3

3 0
3 years ago
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A girl stands on a carousel and rotated around the ride 6 times if the distance between the girl and the center of the carousel
Lesechka [4]

Answer:

301.74 feet

Step-by-step explanation:

Given:

A girl stands on a carousel and rotated around the ride 6 times.

The distance between the girl and the center of the carousel is 8.

It means radius, r = 8 feet

Question asked:

How many feet did the little girl travel ?

Solution:

As here asked that how many feet the little girl traveled during rotation around the ride 6 times, we will find circumference of the circle.

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Now, we will multiply this by 6 as she  rotated around the ride 6 times.

6\times50.29=301.74\ feet

Thus, the little girl traveled 301.74 feet during this ride.

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