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Scorpion4ik [409]
3 years ago
13

Storage fees are 30$/month for 100 boxes, you need to storage 1000 in 6 months calculate the storage fees

Mathematics
1 answer:
Arlecino [84]3 years ago
4 0
30$/ month for 100 boxes
300$/ month for 1000 boxes
1800$/ 6 months for 1000 boxes
answer: 1800$
Hope I helped, please mark Brainliest if the answer is correct! Thanks
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Using factor theorem , show that (x -4) is a factor 2x3 + x2 -26x - 40 and hence factorize completely.
notka56 [123]

Step-by-step explanation:

if x-4 is a factor of 2x^3 + x^2- 26x - 40

then f(4) = 0

f(x) = 2x^3 + x^2- 26x - 40

f(4) = 2(4)^3 + (4)^2 - 26(4) - 40

f(4)= 2(64) + 16 - 104 - 40

f(4) = 128 + 16 - 104 - 40

f(4) = 0

hence factorize completely is the photo

7 0
3 years ago
4(2x + 3) ÷ 5y From the expression above, provide an example of each of the following: sum, term, product, factor, quotient, and
Ann [662]

Answer:

Sum - 2x + 3

term - 2x

Product - 4(2x + 3)

Factor - not present

quotient - (2x + 3) / 5

Coeffecient - 4(2x + 3)

I really hope this helps

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A cold drink is poured out at 52°F. After 2 minutes of sitting in a 72°F room, its temperature has risen to 55°F. Find an equati
I am Lyosha [343]

Answer:

The model for the temperature of the drink can be written as

T=72-20e^{-0.08t}

Step-by-step explanation:

For a cold drink in a hotter room, we can say that the rate of change of temperature of the drink is proportional to the difference of temperature between the drink and the room.

We can model that in this way

\frac{dT}{dt}=k*(T_r-T)

If we rearrange and integrate

\int\frac{dT}{(T-Tr)} =-k*\int dt\\\\ln(T-T_r)=-kt+C1\\\\T-T_r=Ce^{-kt}\\\\T=T_r+Ce^{-kt}

We know that at time 0, the temperature of the drink was 52°F. Then we have:

T=T_r+Ce^{-kt}\\\\52=72+Ce^0=72+C\\\\C=-20

We also know that at t=2, T=55°F

T=T_r+Ce^{-kt}\\\\55=72-20e^{-k*2}\\\\e^{-k*2}=(72-55)/20=0.85\\\\-2k=ln(0.85)=-0.1625\\\\k=0.08

The model for the temperature of the drink can be written as

T=72-20e^{-0.08t}

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