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BARSIC [14]
3 years ago
15

3x^2-192=0

- 192 = 0" alt="3 {x}^{2} - 192 = 0" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Murljashka [212]3 years ago
5 0
3x^2-192=0
3x^2=192
x^2=\frac{192}{3}
x=\pm \sqrt{64}
x=\pm 8

x=-8 and x=8 are the solutions

andreev551 [17]3 years ago
5 0

3 {x}^{2}  - 192 = 0 \\ 3 {x}^{2}  = 192 \\  {x}^{2}  = 64 \\  \\ x  _{ _{1} } =  - 8 \\  x _{ _{2} }  =  8

hope it's correct
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Step-by-step explanation:

This question is solved using the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

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This means that p = 0.07, n = 50

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This is the pvalue of Z when X = 0.02. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.02 - 0.07}{0.036}

Z = -1.39

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So

P(p < .02) = 0.0823

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