Answer:
3n+2
Step-by-step explanation:
hope this helps :(
Well the position function is:
h(t)=-16t^2+256
It will hit the ground when h(t)=0
-16t^2+256=0 factor out -16
-16(t^2-16)=0 factor difference of squares...
-16(t+4)(t-4)=0, since t>0
t=4 seconds
Answer:
height = 20.5068 m
Step-by-step explanation:
Given the data in the question;
First, lets calculate the amplitude, midline and period of 8minutes
Amplitude = 35 / 2 = 17.5
|A| = 17.5
A = - 17.5 { since the wheel starts at 6 o clock }
midline C = (35/2) + 3
C = 17.5 + 3
C = 20.5
And period is 8 minutes
⇒ 2π/B = 8
8B = 2π
B = 2π/8 = π/4
So our equation will be in the form of;
y = h(t) = Acos(B×t) + C
∴ h(t) = -17.5cos( π/4×t) + 20.5
Now, How high are you off the ground after 6 minutes
⇒ height = -17.5cos( π/4 × 6) + 20.5
height = -17.5cos( π/4 × 6) + 20.5
height = -17.5cos( 4.71238898) + 20.5
height = -17.5 × cos( 4.712) + 20.5
height = -17.5 × -0.00038898 + 20.5
height = 0.0068 + 20.5
height = 20.5068 m
Y + R + V = 42
but 4 YEARS AGO : (R-4) +(V-4) = Y
Replace Y in the 1st equation by: (R-4) +(V-4)
(R-4) +(V-4) + R + V = 42
2R - 2V - 8 = 42; 2R -2V = 50, or R+V=25
IF R+V =25 AND Y + R +V = 42, then Y + 25 = 42 and Y =17
Answer:
Here is the ans...Hope it helps :)