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natima [27]
3 years ago
14

What force is required to accelerate a block of mass 4 kg at 2m/s2 on a surface which has a frictional force of 2N.

Physics
1 answer:
Vaselesa [24]3 years ago
3 0

the answer is b your wecome

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In places of hot climate it is advised that the outer walls of houses be painted white. Explain.
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2 years ago
Read 2 more answers
Ohm's law states which relationship between electrical quantities? a. Volts = current x resistance b. Volts = current divided by
miv72 [106K]

Answer:

a. Volts = current x resistance

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V = IR

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7 0
2 years ago
A 1500 kg car is moving on a flat, horizontal flat road. If the radius of the curve is 35 m and
Troyanec [42]

The net force on the car is the friction that keeps it on the road, which points toward the center of the circle of the curve. Then by Newton's second law, we have

• net vertical force:

∑ <em>F</em> = <em>N</em> - <em>W</em> = 0

• net horizontal force:

∑ <em>F</em> = <em>Fs</em> = <em>m a</em>

where

<em>N</em> = magnitude of normal force

<em>W</em> = car's weight

<em>Fs</em> = mag. of static friction

<em>m</em> = car's mass

<em>a</em> = <em>v</em> ²/<em>R</em> = mag. of the centripetal acceleration

<em>v</em> = car's speed

<em>R</em> = radius of curve

Now,

• compute the car's weight:

<em>W</em> = <em>m g</em> = (1500 kg) (9.8 m/s²) = 14,700 N

• solve for the mag. of the normal force:

<em>N</em> = 14,700 N

• solve for the mag. of the friction force, using the given friction coefficient:

<em>Fs</em> = 0.5 <em>N</em> = 7350 N

• solve for the (maximum) acceleration:

7350 <em>N</em> = (1500 kg) <em>a</em>   →   <em>a</em> = 4.9 m/s²

• solve for the (maximum) speed:

4.9 m/s² = <em>v</em> ²/ (35 m)   →   <em>v</em> ≈ 13 m/s

4 0
3 years ago
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