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Elena L [17]
3 years ago
10

someone help me please

Physics
2 answers:
RoseWind [281]3 years ago
7 0
You need a picture but can you please mark me brainliest
Lemur [1.5K]3 years ago
4 0

Answer:

but for helping we need yr ques nd they r not here

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You have to design a loop-the-loop for a new amusement park so that when each car passes the top of the loop inverted (upside-do
elena-14-01-66 [18.8K]

first of all go to slader .com to serach up this answer your welcome they have the best answers

6 0
3 years ago
A piano wire with mass 2.60g and length 84.0 cm is stretched with a tension of 25.0 N. A wave with frequency 120.0 Hz and amplit
likoan [24]

Answer:

Power will be 0.2023 watt

And when amplitude is halved then power will be 0.0505 watt

Explanation:

We have given mass of the Piano wire m = 2.60 gram = 0.0026 kg

Length of wire l = 84 cm = 0.84 m

So mass density \mu =\frac{m}{l}=\frac{0.0026}{0.84}=0.0031kg/m

Tension in the wire T = 25 N

Frequency f = 120 Hz

So angular frequency \omega =2\pi f=2\times 3.14\times 120=753.6rad/sec

And amplitude A = 1.6 mm = 0.0016 m

We have to find the generated power

Power is given by P=\frac{1}{2}\sqrt{\mu T}\omega ^2A^2=\frac{1}{2}\times \sqrt{0.0031\times 25}\times 753.6^2\times 0.0016^2=0.2023watt

From the relation we can see that power P\ \propto\ A^2

So if amplitude is halved then power will be \frac{1}{4} times

So power will be equal to \frac{0.2023}{2}=0.0505watt

4 0
3 years ago
which of the following cannot be increased by using a machine of some kind? work, force, speed, torque
Lemur [1.5K]

Explanation:

Work cannot be increased by using a machine of some kind.

8 0
2 years ago
Help pls they are all going to have the same answers.
Liula [17]
1.activities of daily living.
2.activity of daily living.
3.planned exercises activities.
4. planned exercises activities.
5. activities of daily living.
6. planned exercises activities.
4 0
3 years ago
A parallel circuit contains an 18-V battery wired with 2 bulbs with resistances of 8
RSB [31]

Answer:

See below

Explanation:

Total current will be   18 v/ 8 ohms +   18v / 24 ohms = 3 amps

Equivalent resistance   =   1 / (1/8 + 1/24) = 6 Ω

7 0
2 years ago
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