Question

What is the perimeter of kite OBDE?

Answer 1

Answer:

The correct option is 3. The perimeter of kite OBDE is 27 units.

Step-by-step explanation:

From the figure it is clear that the triangle ABC is right angled triangle.

According to Pythagoras theorem,

$hypotenuse^2=perpendicular^2+base^2$

Using Pythagoras theorem, we get

$AB^2=AC^2+BC^2$

$AB=\sqrt{(15)^2+(8)^2}$

$AB=17$

The diameter of circle of is 17 units. So, the radius of the circle is

$\frac{17}{2}=8.5$

Angle DBO and DEO are right angles it means DB and DE are tangent.

According to the circle tangent theorem the length of tangent from the same point are equal.

$DB=DE=5$

$r=OB=OE=8.5$

Perimeter of kite OBDE is

$Perimeter(OBDE)=OB+DB+DE+OE$

$Perimeter(OBDE)=8.5+5+5+0.8=27$

The perimeter of kite OBDE is 27 units. Therefore the correct option is 3.

Answer 2

the best answer would be 27 units i hope this helps chu