in the number line, the end points are DG, and the point in between is O
DG = 88
DO = 5x + 12
OG = 2x
Set the equation. The two parts (DO & OG) are equal to the whole (DG)
2x + 5x + 12 = 88
Simplify. Combine like terms
(2x + 5x) + 12 = 88
7x + 12 = 88
Isolate the x. Remember to do the opposite of PEMDAS. Subtract 12 from both sides
7x + 12 (-12) = 88 (-12)
7x = 76
Isolate the x. Divide 7 from both sides:
7x/7 = 76/7
x = 76/7
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Find DO. Plug in "76/7" for x:
DO = 5x + 12
DO = 5(76/7) + 12
Simplify. Remember to follow PEMDAS. Multiply 76 with 5
DO = 380/7 + 12
Next, divide 380 with 7
DO = 54.29 (rounded)
Finally, add
DO = 54.29 + 12
DO = 66.29
66.29 is your answer
hope this helps
Answer:
Step-by-step explanation:
to solve this problem we can use the Pythagorean theorem
UT and TL are the legs, while LU is the hypotenuse
We have to find LU so we can proceed like this
x^2 + (x+1)^2 = LU^2
x^2 + x^2 + 1 + 2x = LU^2
2x^2 + 2x + 1 = LU^2
LU = +/- 
we have to take only the positive value because a length can’t be negative.
2x^2 + 2x + 1 is positive for every value of x, so the final answer is
6 greeting cards for 23.40 is the best price! It is $3.90 per each card.
Answer:
y=(-5/3)x+29
Step-by-step explanation:
we will use the base formula y=mx+b
In order to be perpendicular, the slope must be the flipped fraction and have the opposite sign, so our m is (-5/3)
y=(-5/3)x+b
You can plug in the (9,14) point in order to find the b
14=(-5/3)(9)+b
14=(-45/3)+b
14=(-15)+b
14+15=b
29=b
and so altogether our equation is y=(-5/3)x+29
A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the
KM² = KE² + ME²KM² = 8² + (3√5)² = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM) = 1/2 * 3√5 * (40 + 24) = 1/2 * 3√5 * 64 = 3 x 2.23 * 32 = 214.66 units²
