The last net has all of the requirements. All you have to do then is count, which means the vertices from the hexagon all add up to 12. The rectangles are supposed to encircle it to make a closed object, which gives it eight faces, hexagons included.
So you would do is take 3,500 and multiply it by 4% to get 140
For this problem we can represent the situation as a rectangle triangle.
x: depth of water.
40: Base. "Antonio pulls the lily to one side, keeping the stem straight, until the blossom touches the water at a spot"
x + 8: Hypotenuse. "He notices water lily sticking straight up from the water, whose blossom is 8 cm above the water's surface." Antonio pulls the lily to one side, keeping the stem straight, until the blossom touches the water at a spot".
By the Pythagorean theorem we have:
x ^ 2 + 40 ^ 2 = (x + 8) ^ 2
Clearing x:
x ^ 2 + 1600 = x ^ 2 + 16x + 64
x ^ 2 - x ^ 2 = 16x + 64 - 1600
0 = 16x -1536
1536 = 16x
1536/16 = x
x = 96
answer:
1) x ^ 2 + 40 ^ 2 = (x + 8) ^ 2
2) the depth of the water is
x = 96
I think the answer is 43.8.
