Solve for x and y: 7y−5x=31 & x=4−2y
2 answers:
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Q5 - 6: I'm guessing that it's asking us how many less than right angles, right angles, or more than right angles are present in the shapes given in question 5 and 6.
Keep in mind that right angles are exactly 90 degrees. Less than a right triangle is less than 90 degrees ( x < 90) and more than a right triangle is more than 90 degrees (x > 90) View the attachment for further demonstration and explanation.
Based on this, I think you (or your sister) need to re-check question 5. There are no right angles present there, and the lack of the box and L shaped angles indicate this. You are on the right track for number 6 though as only 2 right triangles are present.
For number 8, Kaylee (lol, feels weird saying that since my name is Kaylee), is incorrect. There are no right angles. You can further explain and elaborate on this using the information I supplied you with.
Keep in mind that right angles are exactly 90 degrees. Less than a right triangle is less than 90 degrees ( x < 90) and more than a right triangle is more than 90 degrees (x > 90) View the attachment for further demonstration and explanation.
Based on this, I think you (or your sister) need to re-check question 5. There are no right angles present there, and the lack of the box and L shaped angles indicate this. You are on the right track for number 6 though as only 2 right triangles are present.
For number 8, Kaylee (lol, feels weird saying that since my name is Kaylee), is incorrect. There are no right angles. You can further explain and elaborate on this using the information I supplied you with.
Answer:
0.0039 is the probability that the sample mean hardness for a random sample of 12 pins is at least 51.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 50
Standard Deviation, σ = 1.3
Sample size, n = 12
We are given that the distribution of hardness of pins is a bell shaped distribution that is a normal distribution.
Formula:
Standard error due to sampling =
P(sample mean hardness for a random sample of 12 pins is at least 51)
Calculation the value from standard normal z table, we have,
0.0039 is the probability that the sample mean hardness for a random sample of 12 pins is at least 51.