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Dafna11 [192]
4 years ago
10

During a week in January in Cleveland, Ohio, the daily high temperatures were -4 °F, -2 °F, -12 °F, 5 °F, 12 °F, 16 °F, and 20 °

F. Which expression can be used to find the difference between the highest temperature of the week and the lowest temperature of the week?
Mathematics
1 answer:
KIM [24]4 years ago
6 0

Answer:

\Delta T = T_{max,w} - T_{min,w}

\Delta T = 20\,^{\circ}F - (-12\,^{\circ}F)

\Delta T = 32\,^{\circ}F

Step-by-step explanation:

The expression needed is the highest temperature of the week subtracted by the lowest temperature of the week. That is to say:

\Delta T = T_{max,w} - T_{min,w}

\Delta T = 20\,^{\circ}F - (-12\,^{\circ}F)

\Delta T = 32\,^{\circ}F

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Answer:

They are not co-linear.

Step-by-step explanation:

For three point's to be co linear the slopes of the lines connecting them should be same

Mathematically we can write for (x_{1},y_{1}),(x_{2},y_{2}),(x_{3},y_{3})

to be co-linear we should have

\frac{y_{3}-y_{2}}{x_{3}-x_{2}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{y_{3}-y_{1}}{x_{3}-x_{1}}

Applying the given values we obtain

\frac{y_{3}-y_{2}}{x_{3}-x_{2}}=\frac{8-6}{0-4}=-1/2\\\\\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{6-2}{4-3}=3\\\\\frac{y_{3}-y_{1}}{x_{3}-x_{1}}=\frac{8-2}{0-3}=-2

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6 0
3 years ago
Calculate the perimeter and area of this shape.<br> Perimeter =
konstantin123 [22]
<h3><u>Answer</u><u>:</u></h3>

Perimeter → 25cm

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<h3><u>Explanation</u>:</h3>

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area =  > 3 \times  \frac{1}{2}  \times 2 + 3 \times 3.5 + 6 \times 2 = 3 + 12 + 10.5 = 25.5

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Step-by-step explanation:

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