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grin007 [14]
3 years ago
7

Find the inverse. Restrict the domain as necessary.

Mathematics
2 answers:
joja [24]3 years ago
8 0
To find the inverse function interchange the variable and solve for y
f^-1(x)=x^2-1
trasher [3.6K]3 years ago
6 0
The restrictions would be possible x values that could make the function equal 0.
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\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\

\bf \cfrac{small}{large}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}\implies \cfrac{s}{s}=\cfrac{\sqrt{32}}{\sqrt{50}}\implies \cfrac{s}{s}=\cfrac{\sqrt{16\cdot 2}}{\sqrt{25\cdot 2}}
\\\\\\
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