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3 years ago

How can I divide 33 photos into two groups

Mathematics

1 answer:

melamori03 [73]3 years ago

4 0

You cant 33/2 is like 16.5 i believe so one wouldnt fully make it.

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PLZ help me out with this

Marta_Voda [28]

Answer:

diving the angle into two congruent angles

Step-by-step explanation:

bisecting an angle means dividing the angle into two equal parts

5 0

3 years ago

Easy math please help

insens350 [35]

1) False

Adjacent angles must share a common side/ray.

2) B and D

Adjacent angles are those that are directly next to each other and share a common side.

3) C

Angles 1 and 2 are congruent. Angles 3 and 4 are congruent. Both of these pairs have angles that are opposite each other.

4) B

Angles 1 and 2 add up to 180. Angles 3 and 4 add up to 180. Both of these pairs of angles are supplementary.

5) A

These angles are directly next to each other and share a common side.

Hope this helps!! :)

4 0

3 years ago

Susie wants to buy a snowboard that cost $530. She has already saved $98 for it. She makes $72 a week babysitting. Which inequal

Alex777 [14]

Its B , 6 because if you subtract 98 from 530 you get 432 and if you divide that by 72 you get 6 :)

6 0

4 years ago

DUE IN 10 MINUTES. PLEASE HELP. WOULD BE VERY THANKFUL

Andrej [43]

Answer:

1. y = 36°

a = 9.7

2. No.. wire H to P/Q is not a tangent

Step-by-step explanation:

see below

7 0

3 years ago

4.20. According to a report released by the National Center for Health Statistics, 51% of U.S. households has only cell phones (

Sergeu [11.5K]

Answer:

The probability that the household has only cell phones and has high-speed Internet is 0.408

Step-by-step explanation:

Let A be the event that represents U.S. households has only cell phones

Let B be the event that represents U.S. households have high-speed Internet.

We are given that 51% of U.S. households has only cell phones

P(A)=0.51

We are given that 70% of the U.S. households have high-speed Internet.

P(B)=0.7

We are given that U.S. households having only cell phones, 80% have high-speed Internet. A U.S household is randomly selected.

P(B|A)=0.8

$\frac{P(A\capB)}{P(A)}=0.8\\P(A\capB)=0.8 \times P(A)\\P(A\capB)=0.8 \times 0.51\\P(A\capB)=0.408$

Hence the probability that the household has only cell phones and has high-speed Internet is 0.408

7 0

3 years ago