2 years ago

Of

Mathematics

2 answers:

Serjik [45]2 years ago

6 0

Answer: 18

Step-by-step explanation:

ollegr [7]2 years ago

3 0

The answer is 25 I think sorry if it’s wrong :)

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What is the vertex of the graph of the function below?

balandron [24]

I think it is A
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2 years ago

Could someone please let me know these answers , thank you :)

KATRIN_1 [288]

Answer:

1: CD and BC

2: CE and AC

3: AE , AB , BD, DE

4: AD and BE

There you go!

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3 years ago

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HELP!!!! I WILL GIVE BRAINLIEST TO THE FIRST ANSWER!!!!!!!

aleksklad [387]

I would say c. I’m not sure if I’m right if I’m not sorry but good luck

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3 years ago

Evaluate the line integral for x^2yds where c is the top hal fo the circle x62 _y^2 = 9

natulia [17]

Parameterize $C$ by

$\mathbf r(t)=\langle x(t),y(t)\rangle=\langle3\cos t,3\sin t\rangle$

where $0\le t\le\pi$ . Then the line integral is

$\displaystyle\int_Cx^2y\,\mathrm dS=\int_{t=0}^{t=\pi}x(t)^2y(t)\left\|\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\right\|\,\mathrm dt$
$=\displaystyle\int_{t=0}^{t=\pi}(3\cos t)^2(3\sin t)\sqrt{(-3\sin t)^2+(3\cos t)^2}\,\mathrm dt$
$=\displaystyle3^4\int_{t=0}^{t=\pi}\cos^2t\sin t\,\mathrm dt$

Take $u=\cos t$ , then

$=\displaystyle-3^4\int_{u=1}^{u=-1}u^2\,\mathrm du$
$=\displaystyle3^4\int_{u=-1}^{u=1}u^2\,\mathrm du$
$=\displaystyle2\times3^4\int_{u=0}^{u=1}u^2\,\mathrm du$
$=54$

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3 years ago

Name all the awnsers below

spayn [35]

Answer:

this doesn't look fun.

Step-by-step explanation:

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