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miss Akunina [59]
3 years ago
9

A car experiences a 300 N force to the right from the engine and separate 150 N force due to friction and air resistance to the

left. Will it accelerate to the left, right, or not at all?
Biology
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0

Answer:

right

Explanation:

Given that

Force on the car towards right

\vec{F_1}=300\ N

Force on the car towards left

\vec{F_2}=150\ N

Lets take rightward is positive and in the leftward is negative ,therefore the net force on the car is given as follows

\vec{F_{net}}=\bar{F_1}+\bar{F_2}

\vec{F_{net}}=300-150\ N

\vec{F_{net}}=150\ N

Therefore , we can say that ,the net force will be towards right. That is why the car will move in the right.

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Complete question:

A wild-type tomato plant (Plant 1) is homozygous dominant for three traits: solid leaves (MM), normal height (DD), and smooth skin (PP).

Another tomato plant (Plant 2) is homozygous recessive for the same three traits: mottled leaves (mm), dwarf height(dd), and peach skin (pp).

In a cross between these two plants (MMDDPP x mmddpp), all offspring in the F1 generation are wild type and heterozygous for all three traits(MmDdPp).

Now suppose you perform a testcross on one of the F1plants (MmDdPp x mmddpp). The F2 generation can include plants with these eight possible phenotypes:

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mottled, dwarf, smooth

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Assuming that the three genes undergo independent assortment, predict the phenotypic ratio of the offspring in the F2 generation.

Answer and Explanation:

<u>Cross 1:</u>

Parental) MMDDPP  x  mmddpp

F1) MmDdPp

<u>Cross 2</u>: <em>Testcross</em>

Parental) MmDdPp   x   mmddpp

Gametes) MDP   MdP   MDp  Mdp   mDP   mdP   mDp  mdp

                 mdp   mdp   mdp   mdp   mdp   mdp   mdp   mdp

Punnet Square)

              mdp            

MDP     MmDdPp

MdP     MmddPp

MDp     MmDdpp

Mdp     Mmddpp

mDP     mmDdPp

mdP     mmddPp

mDp     mmDdpp

mdp      mmddpp    

F2) 8/64 = 1/8 MmDdPp, solid leaves, normal height, smooth skin

     8/64 = 1/8 MmddPp,  solid leaves, dwarf height, smooth skin

     8/64 = 1/8 MmDdpp, solid leaves, normal height, peach skin

     8/64 = 1/8 Mmddpp,  solid leaves, dwarf height, peach skin

     8/64 = 1/8 mmDdPp, mottled leaves, normal height, smooth skin

     8/64 = 1/8  mmddPp,  mottled leaves, dwarf height, smooth skin

     8/64 = 1/8  mmDdpp,  mottled leaves, normal height, peach skin

     8/64 = 1/8  mmddpp,  mottled leaves, dwarf height, peach skin

Another way of predicting the phenotypic ratio of the offspring in the F2 generation is by performing a testcross for each gene by separately and then multiplying their genotypic proportions. This is:

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Parental) Mm  x  mm

Gamtes) M  m    m   m

Punnet Square)        M     m

                       m    Mm   mm

                       m    Mm   mm

F2) 1/2 Mm

      1/2 mm

<u><em>High Gene</em></u>

Parental) Dd  x  dd

Gamtes) D  d    d   d

Punnet Square)       D     d

                       d     Dd    dd

                       d     Dd    dd

F2) 1/2 Dd

      1/2 dd

<u><em>Skin Gene </em></u>

Parental) Pp  x  pp

Gamtes) P   p   p   p

Punnet Square)       P    p

                          p   Pp   pp

                          p   Pp   pp

F2) 1/2 Pp

      1/2 pp

To get the phenotypic ratio of the offspring we multiply the genotypic proportion for each trait by the genotypic proportions of the other two traits, like this:

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solid leaves ratio -> 1/2

normal height ratio -> 1/2

smooth skin ratio -> 1/2

MmDdPp ratio: 1/2 x 1/2 x 1/2 = 1/8

  • For plants with solid leaves, dwarf height, smooth skin

MmddPp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8

  • For plants with solid leaves, normal height, peach skin

MmDdpp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8

  • For plants with solid leaves, dwarf height, peach skin

Mmddpp ratio:  1/2 x 1/2 x 1/2 x 1/2 = 1/8

  • For plants with mottled leaves, normal height, smooth skin

mmDdPp  ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8  

  • For plants with mottled leaves, dwarf height, smooth skin

mmddPp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8

  • For plants with mottled leaves, normal height, peach skin

mmDdpp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8  

  • For plants with mottled leaves, dwarf height, peach skin

mmddpp  ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8                    

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