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kodGreya [7K]
3 years ago
9

Graph A

Mathematics
1 answer:
svetlana [45]3 years ago
4 0
Answer:
20x times because you have to figure out the times and hours
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Given ADC ACB and BDC BCA prove a squared + b squared = c squared. Use the two Column proof.
Yuri [45]

Answer:

a²  + b²  = c · (e + d) =  c × c = c²

a²  + b²  = c²

Please see attachment

Step-by-step explanation:

Statement,                                                        Reason

ΔADC ~ ΔACB,          Given

AC/AD = BA/AC,        The ratio of corresponding sides of similar triangles

b/e = c/b

b² = c·e

ΔBDC ~ ΔBCA,           Given

BC/BA =  BD/BC,        The ratio of corresponding sides of similar triangles

a/c = d/a        

a² = c·d

a²  + b²   = c·e + c·d

a²  + b²   = c · (e + d)

e + d = c,                       Addition of segment

a²  + b²   = c × c = c²

Therefore, a²  + b²   = c²

7 0
3 years ago
1) sin 102<br> in standard position
ira [324]

Answer:

What are you asking? Whats the problem?

4 0
3 years ago
Read 2 more answers
The sum of 12 and the quantity 8 times a number k is equal to 48
Rudiy27
12+8k=48
=>8k=36
=>k=36/8
=>k=4.5
6 0
3 years ago
The following information was obtained from independent random samples taken of two populations. Assume normally distributed pop
Volgvan

Answer:

1. The 95% confidence interval for the difference between means is (-5.34, 11.34).

2. The standard error of (x-bar1)-(x-bar2) is 4.

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{9.2195^2}{10}+\dfrac{9.4868^2}{12}}\\\\\\s_{M_d}=\sqrt{8.5+7.5}=\sqrt{16}=4

Step-by-step explanation:

We have to calculate a 95% confidence interval for the difference between means.

The sample 1, of size n1=10 has a mean of 45 and a standard deviation of √85=9.2195.

The sample 2, of size n2=12 has a mean of 42 and a standard deviation of √90=9.4868.

The difference between sample means is Md=3.

M_d=M_1-M_2=45-42=3

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{9.2195^2}{10}+\dfrac{9.4868^2}{12}}\\\\\\s_{M_d}=\sqrt{8.5+7.5}=\sqrt{16}=4

The critical t-value for a 95% confidence interval is t=2.086.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_{M_d}=2.086 \cdot 4=8.34

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = 3-8.34=-5.34\\\\UL=M_d+t \cdot s_{M_d} = 3+8.34=11.34

The 95% confidence interval for the difference between means is (-5.34, 11.34).

6 0
4 years ago
I need help with this please
hoa [83]

Answer:

z = 113

y = 31

Step-by-step explanation:

j || n and line a is their transversal. (given)

Therefore,

z° = 180° - 67° (exterior angles on the same side of transversal)

z°= 113°

z = 113

(5y - 88)° = 67° (exterior alternate angles)

5y - 88 = 67

5y = 67 + 88

5y = 155

y = 155/5

y = 31

7 0
3 years ago
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