Given ADC ACB and BDC BCA prove a squared + b squared = c squared. Use the two Column proof.
1 answer:
Answer:
a² + b² = c · (e + d) = c × c = c²
a² + b² = c²
Please see attachment
Step-by-step explanation:
Statement, Reason
ΔADC ~ ΔACB, Given
AC/AD = BA/AC, The ratio of corresponding sides of similar triangles
b/e = c/b
b² = c·e
ΔBDC ~ ΔBCA, Given
BC/BA = BD/BC, The ratio of corresponding sides of similar triangles
a/c = d/a
a² = c·d
a² + b² = c·e + c·d
a² + b² = c · (e + d)
e + d = c, Addition of segment
a² + b² = c × c = c²
Therefore, a² + b² = c²
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