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Sloan [31]
2 years ago
12

Find zeros from vertex form y=4(x-2)^2

Mathematics
1 answer:
uranmaximum [27]2 years ago
7 0
<h2>Explanation:</h2><h2></h2>

The vertex form of the equation of a parabola is given by the form:

y=a(x-h)^2+k \\ \\ \\ Where: \\ \\ a \ \text{is the leading coefficient and (h,k) the vertex of the parabola:}

The zeroes are the x-values that touches the x-axis, that is, those x-values at which y=0. Form the equation it's easy to know that at x=2 the output y=0 because:

y=4(x-2)^2 \\ \\ If \ x=2: \\ \\ y=4(2-2)^2 \\ \\ y=4(0)^2 \\ \\ y=0

So the only zero occurs at x=2

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