From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.
Using pythagoras theorem,

and

Angle θ is given by

Given that a = 4 units, b = 5 units, and c = 9 units, thus

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.

Given that x is a point on line segment AB, this means that x is a positive number less than 5.
Thus

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
Dividing x5^5 / x5^5 is 1
Answer:
t=1
Step-by-step explanation:
16-2t = t + 9 + 4t
Combine like terms
16-2t = 9 + 5t
Add 2t to each side
16 -2t+2t = 9+5t+2t
16 = 9+7t
Subtract 9 from each side
16-9 = 9-9 +7t
7=7t
Divide each side by 7
7/7 = 7t/7
1 =t
1/3 you can use two formulas but I recommend rise over run