Answer:
mean = 7
median = 7
range = 9
mid range = 7.5
Step-by-step explanation:
3, 5, 6, 7, 7, 9, 12
Range is the difference between the highest and lowest values of a set of observations
Range = highest value - lowest value
12 - 3 = 9
Median can be described as the number that occurs in the middle of a set of numbers that are arranged either in ascending or descending order
3, 5, 6, 7, 7, 9, 12
median = 7
Mean is the average of a set of numbers. It is determined by adding the numbers together and dividing it by the total number
Mean = sum of the numbers / total number
(6 + 12 + 5 + 7+ 7 + 3 + 9) / 7 = 7
Mid range = (highest value + lowest value) / 2
(12 + 3) / 2 = 7.5
Answer:
n 3 is the correct answer okay
Answer:
8/15
Step-by-step explanation:
Answer:
m=2 and n=3
Step-by-step explanation:
<u>Step</u> :-
Given ![[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4](https://tex.z-dn.net/?f=%5B%202%20x%5E%7Bn%7Dy%5E%7B2%7D%20%5D%5Em%20%3D%204%20x%5E6%20y%5E4)
using algebraic formula ![(a^m)^n= a^{mn}](https://tex.z-dn.net/?f=%28a%5Em%29%5En%3D%20a%5E%7Bmn%7D)
now
![2^{m} x^{mn} y^{2m} = 4x^{6} y^{4}](https://tex.z-dn.net/?f=2%5E%7Bm%7D%20x%5E%7Bmn%7D%20y%5E%7B2m%7D%20%3D%204x%5E%7B6%7D%20y%5E%7B4%7D)
now equating 'x' powers, we get
![x^{mn} = x^{6}](https://tex.z-dn.net/?f=x%5E%7Bmn%7D%20%3D%20x%5E%7B6%7D)
....(1)
now
![y^{2m} = y^{4}](https://tex.z-dn.net/?f=y%5E%7B2m%7D%20%3D%20y%5E%7B4%7D)
Equating 'y' powers ,we get
2 m=4
m=2
substitute m= 2 in equation (1)
we get
2 n=6
n=3
verification:-
substitute m=2 and n=3 , we get
![[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4](https://tex.z-dn.net/?f=%5B%202%20x%5E%7Bn%7Dy%5E%7B2%7D%20%5D%5Em%20%3D%204%20x%5E6%20y%5E4)
![(2 x^{3} y^2)^2 = 4 x^6 y ^4\\](https://tex.z-dn.net/?f=%282%20x%5E%7B3%7D%20y%5E2%29%5E2%20%3D%204%20x%5E6%20y%20%5E4%5C%5C)
![4 x^6 y^4 = 4 x^6 y^4](https://tex.z-dn.net/?f=4%20x%5E6%20y%5E4%20%3D%204%20x%5E6%20y%5E4)
both are equating so m= 2 and n=3