Help please I’ll give brainliest

The coordinates of the vertices of quadrilateral ABCD are A(−4, −1) , B(−1, 2) , C(5, 1) , and D(1, −3) .

finlep [7]

Hi there, KawallPotato! :)

Finding the slope of a line is finding the rise over run, or the change in y over the change in x. Let me show you what I mean.

Slope = change in y / change in x

Or in other words, $\frac{y2 - y1}{x2 - x1}$

Let's try it with AB. The first thing to consider is the placement of the letters. The blank space is asking for the slope of point A to point B, which means that the coordinates of A are your y₁ and x₁ values and the coordinates of B are your y₂ and x₂ values.

Put them in the equation like this:

$\frac{2 - (-1)}{-1 - (-4)}$

2 - (-1) is a double negative, so it becomes 2 + 1, which is 3.

-1 - (-4) turns into -1 + 4 for the same reason. The change in x is also 3.

$\frac{3}{3} = 1$ , so the slope of line AB is 1.

Using the same method, we can solve the next three problems.

Coordinates of B: (-1, 2)

Coordinates of C: (5, 1)

Slope: $\frac{1 - 2}{5 - (-1)} = \frac{-1}{5+1} = -\frac{1}{6}$

The slope of BC is -1/6.

Coordinates of C: (5, 1)

Coordinates of D: (1, -3)

Slope: $\frac{1 - (-3)}{5 - 1} = \frac{1 + 3}{5 -1} = \frac{4}{4}$ , so the slope is 1.

Coordinates of A: (-4, -1)

Coordinates of D: (1, -3)

Slope: $\frac{-1 - (-3)}{1 - (-4)} = -\frac{2}{5}$

The slope is $-\frac{2}{5}$ .

Quadrilateral $ABCD$ is not a parallelogram because it has only one pair of parallel opposite sides.

I hope this was helpful. Have a great day. :D

5 0

3 years ago

Please help I suck at math and I have no clue how to do this!!

katrin2010 [14]

Answer:

a- increase slowly

b- decrease quickly

c-increase quickly

d-decrease slowly

7 0

3 years ago

Read 2 more answers

So if you can do expressions with rational numbers, what is the answer to -½+-0.5?

jek_recluse [69]

Answer:

-1

Step-by-step explanation:

The sum of -1/2 and -5/10 is -1.

4 0

3 years ago

Solving multi step equations

hichkok12 [17]

The no-brain way to do it is to

subtract one side from both sides so you have (something) = 0.
divide by the coefficient of the variable.
add the opposite of the constant.

Of course, at some point, you need to simplify the equation so you have something like

... ax + b = 0 . . . . . . where a and b are some constants that may be positive or negative

17) Subtract the right side.

... 10(x +3) -(-9x -4) -(x -5 +3) = 0

... 10x + 30 +9x +4 -x +5 -3 = 0 . . . . . eliminate parentheses

... x(10+9-1) +(30+4+5-3) = 0 . . . . . . . collect terms

... 18x +36 = 0 . . . . . . . . . . . . . . . . . . . simplified

... x + 2 = 0 . . . . . . . . . . . . . . . . . . . . . .divide by 18, the coefficient of x

... x = -2 . . . . . . . . . . . . . . . . . . . . . . . . add the opposite of the constant

19) Add the opposite of the left side.

... 0 = -9(1 +7x) +12(x -12)

... 0 = -9 -63x +12x -144 . . . . . . eliminate parenthses

... 0 = -51x -153 . . . . . . . . . . . . . simplify

... 0 = x +3 . . . . . . . . . . . . . . . . . divide by -51, the coefficient of x

... -3 = x . . . . . . . . . . . . . . . . . . . add the opposite of the constant

_____

If you examine the variable's coefficients you can make a choice of side to subtract that results in a positive coefficient of the variable.

This method puts variable and constant together until the end. The approach usually taught is to separate the variable terms and constant terms. (The number of steps required is the same either way.)

The reason this is "no brain" is that it always works and requires no judgment as to what you add or subtract from where. Applying a little judgment as described above can make it so you're mostly working with positive numbers, but the method works whether the numbers are positive or negative.

6 0

4 years ago

What is the first step for solving the inequality 3y+14=44

uranmaximum [27]

3y+14=44

Answer: First step is to subtract 14 from each side

3y = 30 (divide each side by 3)
y = 30/3, y = 10

7 0

3 years ago